[tex]\sum_{n=1}^\infty \frac{(3x-2)^n}{n n!}[/tex]
is, I think, what you want.
Ratio test is probably best.
[tex]a_n= \frac{|3x-2|^n}{n n!}[/tex]
and
[tex]a_{n+1}= \frac{|3x-2|^{n+1}}{(n+1) (n+1)!}[/tex]
so the ratio is
[tex]\frac{|3x-2|^{n+1}}{(n+1)(n+1)!}\frac{n n!}{|3x-2|^n}= |3x-2|\frac{n}{(n+1)^2}[/tex]
What is the limit of that as n goes to infinity? If that is less than 1, the series will converge.