Radius and Interval of Convergence for (3x-2)^2/n 3^n Series

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SUMMARY

The radius of convergence (ROC) for the series ∑ (3x-2)² / n 3ⁿ is determined using the ratio test. The terms are defined as aₙ = |3x-2|ⁿ / (n n!) and aₙ₊₁ = |3x-2|ⁿ⁺¹ / ((n+1) (n+1)!). The limit of the ratio as n approaches infinity is |3x-2| * (n / (n+1)²). The series converges when this limit is less than 1, leading to the conclusion that the ROC is |3x-2| < 1.

PREREQUISITES
  • Understanding of series convergence tests, specifically the ratio test.
  • Familiarity with the concept of radius of convergence in power series.
  • Basic knowledge of factorial notation and limits in calculus.
  • Ability to manipulate algebraic expressions involving limits.
NEXT STEPS
  • Study the application of the ratio test in more complex series.
  • Explore the concept of interval of convergence for power series.
  • Learn about the limsup test and its application in determining convergence.
  • Investigate other convergence tests such as the root test and comparison test.
USEFUL FOR

Students and educators in calculus, particularly those focusing on series convergence, as well as mathematicians seeking to deepen their understanding of power series behavior.

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Homework Statement



find the radius of convergence and interval of convergence of the series


Σ (3x-2)^2 / n 3^n
n=1


Homework Equations





The Attempt at a Solution

 
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You need to clean up your notation a little bit, but the ROC for this series is easily found using any number of tests. Try the ratio test or the limsup test.
 
\sum_{n=1}^\infty \frac{(3x-2)^n}{n n!}
is, I think, what you want.

Ratio test is probably best.
a_n= \frac{|3x-2|^n}{n n!}
and
a_{n+1}= \frac{|3x-2|^{n+1}}{(n+1) (n+1)!}

so the ratio is
\frac{|3x-2|^{n+1}}{(n+1)(n+1)!}\frac{n n!}{|3x-2|^n}= |3x-2|\frac{n}{(n+1)^2}
What is the limit of that as n goes to infinity? If that is less than 1, the series will converge.
 

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