Radius as a function of Uniform Circular Motion

Click For Summary
SUMMARY

The discussion centers on the relationship between radius and centripetal acceleration in uniform circular motion, specifically through the equations a = v²/r and a = ω²r. It establishes that while a larger radius (r) leads to an increase in velocity (v = ωr), it also implies a decrease in centripetal acceleration when using the first formula, as acceleration is inversely proportional to radius. However, the second formula indicates a direct proportionality between radius and acceleration when angular velocity (ω) is fixed. The resolution lies in recognizing that both equations are consistent when substituting v with ωr, confirming that centripetal acceleration is dependent on both radius and velocity.

PREREQUISITES
  • Understanding of uniform circular motion
  • Familiarity with angular velocity (ω) and linear velocity (v)
  • Knowledge of centripetal acceleration formulas
  • Basic algebra for substituting variables in equations
NEXT STEPS
  • Study the derivation of centripetal acceleration formulas
  • Learn about the implications of fixed angular velocity on circular motion
  • Explore the concept of angular momentum in relation to radius and velocity
  • Investigate practical applications of centripetal acceleration in engineering and physics
USEFUL FOR

Students of physics, educators teaching circular motion concepts, and professionals in engineering fields who require a solid understanding of centripetal acceleration dynamics.

adam.kumayl
Messages
6
Reaction score
0
How exactly does radius affect centripetal acceleration? In one formula we have (a=v^2/r) which implies inversely proportional, while in the other we have (a=(w^2)*r) which implies directly proportional. I understand that increasing r increases velocity (v=w*r) which means the right answer is increasing r increases acceleration, however how do we justify that increasing r would decrease a in the formula (a=v^2/r)?

Also how can I intuitively makes sense of this? Does increasing r not mean that the same velocity has more time to change (as Khan Academy states at 3:29-4:32) -->

This MIT lecture at 5:40-6:21, states that the acceleration would decrease as radius decreases.
http://www.youtube.com/watch?v=Otmg0-knGtE&list=ECF688ECB2FF119649

So which is it ? They seem to be saying opposite things. Am I misunderstanding something?

p.s. this site is amazing that people contribute their time and knowledge for free to help someone else they will never meet in their life. Truly thank you from one sentient being to another.
 
Last edited by a moderator:
Physics news on Phys.org
well, it depends if you want to hold omega fixed, or velocity fixed. The idea is that the centripetal acceleration must be a specific value, so that a perfect circle is made. So to keep to that requirement, if you have a larger radius, you must have a smaller omega. And equivalently, you must have a larger velocity.
 
adam.kumayl said:
How exactly does radius affect centripetal acceleration? In one formula we have (a=v^2/r) which implies inversely proportional, while in the other we have (a=(w^2)*r) which implies directly proportional. I understand that increasing r increases velocity (v=w*r) which means the right answer is increasing r increases acceleration, however how do we justify that increasing r would decrease a in the formula (a=v^2/r)?

Also how can I intuitively makes sense of this? Does increasing r not mean that the same velocity has more time to change (as Khan Academy states at 3:29-4:32) -->

This MIT lecture at 5:40-6:21, states that the acceleration would decrease as radius decreases.
http://www.youtube.com/watch?v=Otmg0-knGtE&list=ECF688ECB2FF119649

So which is it ? They seem to be saying opposite things. Am I misunderstanding something?

p.s. this site is amazing that people contribute their time and knowledge for free to help someone else they will never meet in their life. Truly thank you from one sentient being to another.


So you've got a rotating disk, and you're interesting in the centripetal acceleration acting on a point on the disk at distance r from the centre of rotation.

For a given angular rotational frequency, the centripetal acceleration acting on the point is proportional to r, as your second equation says.

The reason your first equation seems to disagree is it because it contains v, the velocity of the specific point you are looking at. But the velocity of that point also depends on its distance from r, from the equation v = wr. So when you make r bigger, you are also making v bigger.

Substitute v=wr into your first equation and you will see that both are saying the same thing.
 
Last edited by a moderator:

Similar threads

  • · Replies 4 ·
Replies
4
Views
853
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 37 ·
2
Replies
37
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K