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## Homework Statement

A doubly ionized atom (charge = +2e) whose mass is 5.15E-26 kg is accelerated by a voltage of 3450 V and enters a region where a uniform magnetic field B = 0.100 T acts perpendicular to its motion. What is the radius of curvature of the path of the ion in the B-field?

## Homework Equations

r=[tex]\frac{mv}{qB}[/tex]

e = 1.602 x 10

^{-19}

## The Attempt at a Solution

Given the equation above this is a very simple problem except I don't know how to calculate the velocity of the ion from voltage. The only idea I had was conservation of energy: K

_{f}= U

_{i}or [tex]\frac{1}{2}[/tex]mv

^{2}= q[tex]\Delta[/tex]V. But this ended up wrong and in retrospect I'm not sure if it entirely makes sense to begin with...