Solving for Radius in Magnetic Field: q of Sr+?

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SUMMARY

The discussion focuses on calculating the radius (R) of the path of Strontium ions (Sr+) in a magnetic field using the Lorentz Force equation. The ions are accelerated through a potential of 500 V in a uniform magnetic field of 1 T. The derived formula for radius is r = (2mV/qB)^(1/2), where m is the mass of the ion, V is the potential, q is the charge, and B is the magnetic field strength. The charge (q) for Sr+ is confirmed to be equal to the elementary charge (e) due to the loss of one electron.

PREREQUISITES
  • Understanding of the Lorentz Force and its application in ion separation.
  • Familiarity with basic physics equations, specifically r = mv/qB and E = qV.
  • Knowledge of atomic mass units (AMU) and their conversion to kilograms.
  • Basic chemistry concepts regarding ionization and charge of ions.
NEXT STEPS
  • Study the derivation of the Lorentz Force equation in detail.
  • Learn about mass spectrometry and its applications in isotope separation.
  • Explore the concept of charge-to-mass ratio in different ions.
  • Investigate the effects of varying magnetic field strengths on ion trajectories.
USEFUL FOR

This discussion is beneficial for physics students, chemists, and professionals involved in mass spectrometry or ion separation techniques, particularly those working with charged particles in magnetic fields.

wjdgone

Homework Statement


The Lorentz Force can be used to sort ions (atomic or molecular) based on their charge to mass ratio. This configuration has been used to separate isotopes and as a mass spectrometer. A beam of Strontium ions Sr+ is accelerated through a potential of 500 V and injected into a region of uniform 1 T magnetic field pointed out of the page. Strontium has an atomic mass of approximately 87 AMU (AMU = 1.66 10−27 kg ). Find R in cm.

Homework Equations


r = mv/qB (vector arrows where necessary)
E = qV = (1/2)mv^2

The Attempt at a Solution


[/B]
I solved for v with the second equation and plugged that value in the first equation and got r = (2mV/qB)^1/2, which I'm fairly certain that I'm supposed to get. What I don't get is how to solve for q (nor could I find a value online). Everything else is given; is there an equation I'm missing or something? Is q=e because Sr+ has one less electron? It's been a long time since I've done chemistry haha..
 
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wjdgone said:
got r = (2mV/qB)^1/2
This isn't quite right. Check your derivation.

Is q=e because Sr+ has one less electron?
Yes.
 
TSny said:
This isn't quite right. Check your derivation.

Ah, I see. Thanks for your help.
 

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