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## Homework Statement

(a) What voltage will accelerate electrons to a speed of ##6.00 \times 10^{-7} m/s## ? (b) Find the radius of curvature of the path of a proton accelerated through this potential in a 0.500-T field and compare this with the radius of curvature of an electron accelerated through the same potential.

## Homework Equations

$$r=\frac{mv}{qB}

\\ q\Delta V = \Delta U

\\ K = \frac{1}{2}mv^2 = -\Delta U$$

## The Attempt at a Solution

For the first part I used the second equation and set it equal to the kinetic energy, K. This gave a potential difference of ##1.02 \times 10^{-24} V##. Then for the b), I used the first equation to solve for ##r = |-6.82 \times 10^{-18}| = 6.82 \times 10^{-18}##. Though I was unsure of how to solve for the radius of curvature when accelerated through the same potential, nor how to compare the two values. Also, should the r value been negative, or am I missing a negative sign in one of the values?

Thank you in advance