Radius of Satellite Orbit - 2.1 Days Period

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SUMMARY

A satellite with a period of 2.1 days orbits the sun, and its orbital radius can be calculated using the formula T = 2πr/V. To find the radius, it is essential to convert the period from days to seconds. The velocity can be derived from the equations v = 2πr/T and v² = GM/r, where G is the gravitational constant and M is the mass of the sun. This approach eliminates the need to calculate the actual speed of the satellite, focusing solely on determining the radius of its orbit.

PREREQUISITES
  • Understanding of orbital mechanics
  • Familiarity with gravitational equations
  • Knowledge of unit conversion (days to seconds)
  • Basic algebra and manipulation of equations
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  • Study the derivation of Kepler's laws of planetary motion
  • Learn about gravitational constant (G) and its applications
  • Explore centripetal force equations in orbital dynamics
  • Investigate the relationship between period and radius in circular orbits
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Students in physics, particularly those studying orbital mechanics, as well as educators looking to clarify concepts related to satellite motion and gravitational forces.

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Homework Statement


A satellite orbits the sun with a period of 2.1 day. What is the radius of its orbit?


Homework Equations



T=2pi*r/V

The Attempt at a Solution



If the time is given in days I have to convert to seconds right? Also how would I find velocity would I use V=square root (Gms/r)? For some reason gravity has got me confused
 
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If the time is given in days I have to convert to seconds right?

That would be useful, as the units of G involve seconds.

Recognize that

v = 2πr/T

and m*v2/r = GMm/r2 or as you have written

v2 = GM/r

Combine with

v2 = (2πr/T)2 = GM/r
 
so that actually gets rid of the actual speed of the object as far as usefulness in the equation.
 
Last edited:
Alternatively you could also use m \omega^2 r as the centripetal force.
 
That is an awesome way to check yourself since he wants the work done by using the gravity equations but just to double check myself I can use that! Thats a big help also thank you!
 
talaroue said:
so that actually gets rid of the actual speed of the object as far as usefulness in the equation.

Well ... yes. They only ask you for the radius. Were you invested in wanting to find the speed?
 
No, but I just didn't even think about using the equations that deal with velocity. So I was getting lost. Is there another way to go about this problem?
 
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