RAIN FALL QUESTIONS-CAN'T FIND PART 4 about kg

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Homework Help Overview

The problem involves calculating the mass of water that falls on one acre of land during a thunderstorm, given a rainfall of 0.9 inches. The original poster has successfully calculated the volume of water in different units but is seeking assistance specifically for converting this volume into kilograms.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between mass, volume, and density, specifically using the formula ρ=m/V. There are questions about the density of water and how to apply it to find the mass from the given volume.

Discussion Status

Some participants have provided guidance on using the density of water to calculate mass, while others express confusion about the application of the formula and the values involved. Multiple interpretations of the problem are being explored, particularly regarding the calculations needed to arrive at the mass in kilograms.

Contextual Notes

There is a repeated emphasis on the density of water being 1000 kg/m³, and the volume calculated is 92.5111378 m³. The original poster is under the impression that they need help specifically with the final conversion to kilograms.

tmoney23
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RAIN FALL QUESTIONS---CAN'T FIND PART 4 about kg!

Homework Statement



During a thunderstorm, a total of 0.9 inches of rain falls. How much water falls on one acre of land? (1 mi2 = 640 acres) Express your answer in the following ways.

I found ft^3, m^3, and in^3, but I'm stumped on part 4...where it asks for kg??

Homework Equations



I found 564376 in^3, 3267 ft^3, and 92.5111378 m^3 and I know these 3 parts are 100 percent correct?
JUST NEED HELP WITH PART 4 ON HOW TO FIND kg!
Thanks in advance guys!


The Attempt at a Solution

 
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A relevant equation you will need is density, ρ=m/V.

What is the density of water ?
 


SORRY!

NOTE: Density of 1000kg/m^3!

Thanks. sorry again
 


tmoney23 said:
SORRY!

NOTE: Density of 1000kg/m^3!

Thanks. sorry again

Well then, if you have the formula ρ=m/V, you know 'ρ' and you know 'V', you want to find 'm', rearrange the formula and make 'm' the subject.
 


i still don't get it? i know my mass is x, what is the density in this problem? Would i take the 1000kg/92.5111378 m^3? and then my volume is 92.5111378 m^3...so I would get m=dv...so d=10.8095 and then v is 92.5111378 m^3, d times v equals 1000?
 


tmoney23 said:
i still don't get it? i know my mass is x, what is the density in this problem? Would i take the 1000kg/92.5111378 m^3? and then my volume is 92.5111378 m^3...so I would get m=dv...so d=10.8095 and then v is 92.5111378 m^3, d times v equals 1000?

m=ρV.

You told me density ρ=1000kg/m3

And the volume V=92.5111378m3?

Just substitute into the formula.
 


SO the answer is 1000kg after doing the math out?
 

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