# Time for a Droplet of Water to Fall .25m from Hole

1. Nov 27, 2012

Time for Droplet of Water to Fall .25m from Hole

1. The problem statement, all variables and given/known data

A cylindrical tank .7m tall is filled with water and placed on a stand (below it) that is .3m tall. A hole of radius .001 m in the bottom of tank is opened. Water then flows through the hole and through an opening in the stand and is collected in a tray .3 m below the hole. At the same time, water is added to the tank at an appropriate rate so that the water level in the tank remains constant.
Find:
^The speed at which the water flows out from the hole
[Done: 3.7 m/s]
^The volume rate at which water flows out from the hole
[Done: 1.1623893 x 10-5 m3/s]
^The volume of water collected in the tray in 2 minutes
[Done: .0013948672 m3]
^ ! The time it takes for a droplet of water to fall 0 .25 m from the hole.

2. Relevant equations

Density of Water: 1000 kg/m3

3. The attempt

- PART D -

*The time it takes for a droplet of water to fall 0 .25 m from the hole.
ΔX = V°*t + (1/2)*a*t2
-
.25 = 3.7t + (1/2)(9.8)t2
-
4.9t2 + 3.7t - 0.25 = 0
- Used Quadratic Equation but answer turned out negative and does not match answers -
? ? ?
Correct Answer: 0. 062 seconds
My question is how.

Last edited: Nov 27, 2012
2. Nov 27, 2012

### Staff: Mentor

Re: Fluid Motion

Show your quadratic formula workings. Something must've gone awry, because I get two results and one of them matches the expected value.

3. Nov 27, 2012