Raindrop free falling -- calculate the velocity and time

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SUMMARY

The discussion focuses on calculating the time and velocity of raindrops falling from a height of 19.6 meters, with a gravitational acceleration (g) of 9.81 m/s². The time for each drop to reach the ground is derived using the equation t = sqrt(s/(U + 0.5a)), where 's' is the distance fallen. The velocity of the drops upon reaching the ground is determined, and the speed at a height of 14.7 meters is also calculated, emphasizing the need to clarify the height reference in the calculations.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Familiarity with gravitational acceleration (g = 9.81 m/s²)
  • Basic algebra for solving equations
  • Concept of free fall and neglecting air resistance
NEXT STEPS
  • Learn how to apply kinematic equations for free fall scenarios
  • Study the concept of initial velocity (U) in motion equations
  • Explore the effects of air resistance on falling objects
  • Practice calculating velocities at various heights during free fall
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in understanding the principles of free fall and motion under gravity.

chemie726283
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Homework Statement


Raindrops fall from a broken gutter at 1.0 s intervals to the ground , 19.6 m below

Neglecting air resistance and taking g as 9.81 calculate
  1. the time for each drop to reach the ground
  2. velocity of the drops as they reach the ground
  3. speed of drop at the height of 14.7 m
I would really be grateful if someone could telll me if my answers are right and help me with an approach to nr 3)

Homework Equations

The Attempt at a Solution


  1. t= sqrt of (s/(U+0.5a))
  2. sqr.2x9.81x19.6
  3. I don't know how to approach this
 
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chemie726283 said:

Homework Statement


Raindrops fall from a broken gutter at 1.0 s intervals to the ground , 19.6 m below

Neglecting air resistance and taking g as 9.81 calculate
  1. the time for each drop to reach the ground
  2. velocity of the drops as they reach the ground
  3. speed of drop at the height of 14.7 m
I would really be grateful if someone could telll me if my answers are right and help me with an approach to nr 3)

Homework Equations

The Attempt at a Solution


  1. t= sqrt of (s/(U+0.5a))
  1. what is U here?
    [*]sqr.2x9.81x19.6
    ok
    [*]I don't know how to approach this
    you found the speed at 19.6m; do the same for 14.7m. But be careful: it says at a height of 14.7m, not 14.7m below the gutter!
[/QUOTE]
 
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