Raman Effect and Fluorescence: Understanding the Differences and Mechanisms

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Homework Help Overview

The discussion centers around the differences between the Raman effect and fluorescence, exploring the mechanisms of photon absorption and emission in both phenomena. The original poster expresses confusion regarding the nature of photon interactions in fluorescence versus Raman scattering, particularly concerning energy levels and transitions.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to clarify whether photons are completely absorbed in fluorescence and how this compares to the scattering process in the Raman effect. They question the fate of energy emitted by excited molecules and seek to understand the definition of "ground electronic state." Other participants explore the nature of energy transitions and the differences in absorption processes between the two effects.

Discussion Status

Some participants have provided insights into the absorption processes and energy transitions involved in fluorescence and Raman scattering. There is ongoing exploration of how to differentiate between the two effects, with various interpretations being discussed. The conversation remains open, with no explicit consensus reached yet.

Contextual Notes

Participants note the lack of responses to the original post, indicating a potential challenge in engaging the forum community on this topic. The discussion also touches on the complexities of energy levels and transitions, suggesting that assumptions about electronic versus vibrational states may need further examination.

ananthu
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Homework Statement


I understand that in the fluorescence, the incident photon is absorbed by the molecule, and the molecule while returning to its original ground level releases lesser energy. Similarly, in Raman effect also a photon is incident on a liquid molecule. In stokes' lines the lesser frequency is emitted and in the Anti stokes' lines the greater frequency is released. My doubt is: Is the photon completey absorbed by the molecule and the exited molecule gives up a lesser or greater energy in the form of photons (as in the case of fluorescence) or the collided photon itself is simply bounced from the liquid molecule and come out with changed frequencies? In that case what about the energies emitted by the excited molecules themselves while returning to the ground level? Where do they go? Do they also accompany the scattered photons? Also what does a "ground electronic state" exactly stand for? Is it for the K- level of a molecule, ie. the level corresponding to the principal quantum number 1?


Homework Equations





The Attempt at a Solution

 
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Even after several days of posting this question in the forum, I am surprised why I have not got a single reply! Kindly,any one, share your views...
 
If the photon is absorbed, it is completely absorbed, since its energy will match the gap between the energy levels of the atom. When the atom falls back to the ground state, it might not do so in one step, but instead it might have several transition states. If so, at each transition, the energy is released as a photon of lesser energy (than the original incident one).

A photon will not bounce off and have a different frequency.

Ground state is the state of lowest energy, before being excited by the incoming photons.
 
Thank you for your reply. In one of the texts it is given like this. ie."in fluorescence a photon is completely absorbed whereas it is not so in raman effect". Also in fluoresnce only higher freqency photon is absorbed and the radiation given out is always that of a lower frequency one.. But in raman effect both lower and higher frequencies are given out..
Then how do we exactly differentiate between the two?
Is it that in fluorescence the absorption takes place beteen two real electronic states whereas in the latter the absorption takes place only between vibrational states? So both are the cases of absorptions only?
Is it also possible that an excited atom receives energy from the colliding photon, goes to a higher vibrational state, not an electronic one, returns to the ground state by emitting some infrared lines along with the photon which hit the atom and lost part of its energy? what I mean is that since the infrared emissions can not be seen and therefore we see only the photon bounced with lesser frequency as stokes' line?
 

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