Range of alpha particles in a silicon detector

Click For Summary
SUMMARY

The discussion focuses on calculating the range of alpha particles in silicon using the stopping power formula, specifically integrating the stopping power, \(\frac{dE}{dx}\), to find the range \(R\). Users emphasize the importance of understanding the units of range expressed in g/cm², which accounts for the mass density of the material, rather than simply using centimeters. The integration process can be initiated by assuming a constant stopping power, and the conversion from g/cm² to cm involves dividing by the density of silicon.

PREREQUISITES
  • Understanding of stopping power in particle physics
  • Familiarity with integration techniques in calculus
  • Knowledge of density and its role in radiation absorption
  • Basic concepts of alpha particle interactions with matter
NEXT STEPS
  • Learn about the integration of stopping power in particle physics
  • Study the relationship between density and radiation absorption
  • Explore the NIST ASTAR database for stopping power values
  • Investigate the physics behind unit conversions in radiation measurements
USEFUL FOR

Physicists, researchers in radiation detection, and students studying particle interactions will benefit from this discussion, particularly those focused on alpha particle behavior in materials like silicon.

neural_jam
Messages
17
Reaction score
0
Hi,
I'm trying to find the range of α-particles in silicon; I can work out the stopping power, \frac{dE}{dx}, but the reference I'm using then states that I need to integrate it as follows:

R=\int_T^0 (-\frac{dE}{dx} ) ^{-1} dE

The thing is, I'm not sure as to how to even start this integration, can anyone help?

I can actually look up the value using the page below to calculate it, but I'd like to check it by doing it myself.

http://physics.nist.gov/PhysRefData/Star/Text/ASTAR.html

Also this page gives the units of range in g/cm2, can anyone explain why it's this and not just cm or m? I've seen in other places where g/cm2 and cm seem to be interchangeable, so if it gives the range as 7.375x 10-03g/cm2, can I just use it as 7.375x 10-03cm?

Many thanks!
 
Physics news on Phys.org
neural_jam said:
Hi,
The thing is, I'm not sure as to how to even start this integration, can anyone help?

Also this page gives the units of range in g/cm2, can anyone explain why it's this and not just cm or m? I've seen in other places where g/cm2 and cm seem to be interchangeable, so if it gives the range as 7.375x 10-03g/cm2, can I just use it as 7.375x 10-03cm?

Try to do the integration by assuming a constant stopping power. The stopping power is different for different alpha energies, but gives at least an estimation of the range. What is the kinetic energy of your alpha particle?

You of course cannot make g/cm2 to cm just by changing the unit. What happens if you multiply this by the density of silicon?
 
deccard said:
You of course cannot make g/cm2 to cm just by changing the unit. What happens if you multiply this by the density of silicon?

Did you mean divide it by the density of Si? If so you get cm, which is very useful, thankyou.

However, I don't quite understand what I'm doing when I do this; I mean how do they get to the g/cm2 units in the first place? Also, why do they use this unit for range instead of cm or m or whatever?

Many thanks
 
Last edited:
neural_jam said:
Did you mean divide it by the density of Si? If so you get cm, which is very useful, thankyou.

However, I don't quite understand what I'm doing when I do this; I mean how do they get to the g/cm2 units in the first place? Also, why do they use this unit for range instead of cm or m or whatever?

*Ahem*, Yes I mean divide. Thicknesses are many times given in g/cm2 for for example beam target's. This is because the absorption of radiation in a target is dependent on the mass in the target.

2 cm gaseous nitrogen target is very different from 2 cm lead target. Instead of saying that you have 2 cm nitrogen target with density of 1.03mg/cm3 and 2 cm lead target with density of 11.3g/cm3, you could just say that you have targets with thicknesses 2.06mg/cm2 and 22.6g/cm2 without actually mentioning the target material and people already have an idea how radiation is absorbed in the target.

What a about the integration did you get it?
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
8
Views
5K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
3
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
9K