Ranking velocities of particles in uniform magnetic field

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SUMMARY

The discussion centers on ranking the velocities of five equal-mass particles (A–E) in a uniform magnetic field. The formula used is v = qBr/m, indicating that velocity is dependent on charge, magnetic field strength, and radius of curvature. Participants concluded that while A > B > C=E based on their trajectories, the velocity of particle D, which is neutral, cannot be determined due to the lack of charge information. Ultimately, the problem highlights the importance of charge in determining particle behavior in magnetic fields.

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  • Understanding of magnetic fields and forces on charged particles
  • Familiarity with the equation v = qBr/m
  • Knowledge of particle motion in circular paths
  • Concept of charge and its effect on particle trajectories
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  • Explore the implications of charge neutrality in particle dynamics
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  • Investigate the role of charge in determining particle motion in different fields
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Physics students, educators, and researchers interested in electromagnetism and particle dynamics in magnetic fields.

Linus Pauling
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1. Five equal-mass particles (A–E) enter a region of uniform magnetic field directed into the page. They follow the trajectories illustrated in the figure.

1011734.jpg


Rank from largest to smallest velocity




2. qvBsin(theta) = ma
qvB = ma = m(v^2/r)
v = qBr/m




3. Based on their radii, it should be A > B > C=E

But what about D? It is neutral, so has no radius because it doesn't go in a circle, but clearly has a velocity despite r = 0. Is the answer indeterminate, then?
 
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I think you're meant to assume that all particles have the same charge; otherwise, the problem would be unsolvable. So assuming they have the same charge, D appears to go straight because it's barely affected by the magnetic field. What does that tell you about its velocity?
 
The answer actually was that it couldn't be determined.

Now I am asked to rank the speeds largest to smallest of A, B, C, and E. I thought it was clearly A > B > C=E, but it is not and it tells me this:

The radius of the trajectory of a particle depends on more than just its speed. Be sure not to make assumptions about the relative magnitudes of the charges.

WTF?
 
Linus Pauling said:
v = qBr/m

The velocity depends on the charge, and you are not given any information about the charges. Therefore the problem is not solvable.
 
nvmm
 
Last edited:

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