Rate Determining Step: Explained & Contradicted

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SUMMARY

The discussion centers on the concept of the rate determining step in chemical reactions, specifically addressing a scenario where a slow elementary reaction takes 2 seconds, followed by a fast step that takes 1 second. Despite the total reaction time being 3 seconds, the fast step is disregarded in determining the rate law because it does not influence the overall rate. The faster step consumes products from the slower step more rapidly than they are produced, rendering it ineffective in altering the reaction rate.

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If a slow elementary reaction between two colliding species takes 2 s, and a fast step afterwards takes 1 s the total time is 3 s. Since the time for the overall reaction's completion is increased by the fast step, why is it ignored in determining the rate law? Thanks,

P.S. This is not a homework question, this is an example I thought of that seems to contradict the use of the rate determining step.
 
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Because the faster step depends on the slower step.

The faster step will consume the products of the slower step faster than new products are being made. Because of this, the faster step has no real effect on the rate.
 
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