- #1

shocklightnin

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## Homework Statement

The position of a particle is given by the equation

s = 2t^3 + 36t^2 − 168t

where t is measured in seconds and s in meters.

What is the total distance traveled by the particle after the first seventeen seconds?

## Homework Equations

s(t) = 2t^3 + 36t^2 − 168t

s'(t) = 6t^2+72t-168 = v(t)

## The Attempt at a Solution

ive set t = 17 but it doesn't give me the right answer. (i get 17374). what am i doing wrong?! i know that the particle is at rest after 2 seconds (by taking derivative of this function to get the velocity function). the particle is moving forward in time interval t>2 and moving backward in time interval t<2.R