Find expression in terms of time for a particle's velocity?

Click For Summary
SUMMARY

The particle's acceleration is defined as (2 - 2t) cm/s², leading to the expression for velocity after t seconds being v = -t² + 2t + 8 cm/s. The initial condition provided states that three seconds after passing point O, the particle's velocity is 5 cm/s. The correct anti-differentiation yields the velocity function, confirming that the particle's motion is governed by the specified acceleration throughout its trajectory.

PREREQUISITES
  • Understanding of basic calculus, specifically anti-differentiation.
  • Familiarity with kinematic equations in physics.
  • Knowledge of particle motion concepts, including velocity and acceleration.
  • Ability to interpret initial conditions in motion problems.
NEXT STEPS
  • Review anti-differentiation techniques in calculus.
  • Study kinematic equations and their applications in physics.
  • Explore examples of particle motion problems involving variable acceleration.
  • Learn how to set up and solve simultaneous equations in motion contexts.
USEFUL FOR

Students studying physics or calculus, particularly those focused on motion and kinematics, as well as educators seeking to clarify concepts related to particle velocity and acceleration.

Smeato24
Messages
2
Reaction score
0

Homework Statement


A particle moves along a straight line so that its acceleration t seconds after passing a fixed point O on the line is (2 - 2t) cm/s2. Three seconds after passing O, the particle has a velocity of 5 cm/s. Find and expression, in terms of t, for the velocity of the particle after t seconds.

Homework Equations


a = dv/dt = d2x/dt2

The Attempt at a Solution


From the information, a = -2t + 2 when x = 0, and therefore, by anti-differentiating, v = -t2 + 2t + c.
I assume that the acceleration of the particle stays at -2t + 2 cm/s2 for the rest of its motion, and so tried substituting (t + 3) in for t to get: -2t - 4, the acceleration of the particle after 3 seconds. Here I got stuck. Do I set up simultaneous equations and eliminate? Have I done my anti-differentiation wrong?

Any help appreciated,
Smeato
 
Physics news on Phys.org
Smeato24 said:

Homework Statement


A particle moves along a straight line so that its acceleration t seconds after passing a fixed point O on the line is (2 - 2t) cm/s2. Three seconds after passing O, the particle has a velocity of 5 cm/s. Find and expression, in terms of t, for the velocity of the particle after t seconds.

Homework Equations


a = dv/dt = d2x/dt2

The Attempt at a Solution


From the information, a = -2t + 2 when x = 0, and therefore, by anti-differentiating, v = -t2 + 2t + c.
I assume that the acceleration of the particle stays at -2t + 2 cm/s2 for the rest of its motion, and so tried substituting (t + 3) in for t to get: -2t - 4, the acceleration of the particle after 3 seconds. Here I got stuck. Do I set up simultaneous equations and eliminate? Have I done my anti-differentiation wrong?

Any help appreciated,
Smeato

You have a correct antderivative, but from there onwards your logic is wrong. Go back and read again exactly what the question tells you.
 
Thanks Ray, it really was a simple question!
"t seconds after passing O" means that you start counting at zero at the Origin :)

The correct answer is: v = -t2 + 2t + 8
 

Similar threads

Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K