A particle moves along a straight line so that its acceleration t seconds after passing a fixed point O on the line is (2 - 2t) cm/s2. Three seconds after passing O, the particle has a velocity of 5 cm/s. Find and expression, in terms of t, for the velocity of the particle after t seconds.
a = dv/dt = d2x/dt2
The Attempt at a Solution
From the information, a = -2t + 2 when x = 0, and therefore, by anti-differentiating, v = -t2 + 2t + c.
I assume that the acceleration of the particle stays at -2t + 2 cm/s2 for the rest of its motion, and so tried substituting (t + 3) in for t to get: -2t - 4, the acceleration of the particle after 3 seconds. Here I got stuck. Do I set up simultaneous equations and eliminate? Have I done my anti-differentiation wrong?
Any help appreciated,