Ratio of a ray of light with a refracted ray

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anantchowdhary
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Hey sum1 please tell me that :

if d1=Ray of light through a glass slab(dotted line ie extension of unrefracted ray)


and if d2=Refracted ray

is d1/d2=mu(refractive index)
 
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How do you divide two light rays? What kind of quantity are [itex]d_1[/itex] and [itex]d_2[/itex]? Angle, distance, wavelength, whatever? :confused:
 
d1 is the length of the unrefracted ray(extension of the incident ray into the glass slab) .d2 is the length of refracted ray
 
Friend ! u r saying that what's the ratio of lengths of rays - the extended incident one and the refracted one...in normal diagram u join the initial rays such that triangle formed by normal & inc. ext. =~ triangle by normal & incident(initial) ray...now...apply geo. u get d1/d2 =sin(90-r) / sin(90-i) which is not equal to mu...as angles formed are i & r & not their complements...
 
ofcourse i kno that...but that's wat happens when u do it experimentally
 
I am sure the angles u took in experiments was pi/4..45...and students often take it...
 
Well no...this was in two different cases
 
Well...if u sketch the path of light...and then measure the length it covered
before exiting the slab
 
So they are not true.

Call h be the thickness of the slab, then

d1=h/cosi
d2=h/cosr

where i and r are initial and refraction angles

It's clear that d1/d2=cosr/cosi, while n=sini/sinr

They are equal only if sinrcosr=sinicosi or i+r=90 degrees

or tani=n

Just true at Brewster angle!
 
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