Ratios of Line Segments in Parallelogram ABCD: Divide BC & AE

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SUMMARY

The discussion centers on determining the ratios in which point F divides line segments BC and AE in parallelogram ABCD, where DC is extended to E with a ratio of DE:EC set at 3:2. The division-point theorem is referenced as a potential solution method, specifically the formula OP=[b/(a+b)]*OA +[a/(a+b)]OB. The user expresses confusion regarding the application of this theorem due to the external division of point E and the relationship between segments ED and EC.

PREREQUISITES
  • Understanding of the division-point theorem in geometry
  • Familiarity with external division of line segments
  • Basic knowledge of parallelogram properties
  • Ability to apply ratios in geometric contexts
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  • Study the division-point theorem in detail with examples
  • Explore external division of points in geometry
  • Review properties and theorems related to parallelograms
  • Practice problems involving ratios of line segments in geometric figures
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Students studying geometry, particularly those focusing on properties of parallelograms and the application of the division-point theorem.

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Homework Statement


in the parallelogram ABCD, DC is extended to E so that DE:EC= 3:2. The line AE meets BC at F. Determine the ratios in which F divides BC and F divides AE

The Attempt at a Solution



so i figured i could use the division-point theorem

OP=[b/(a+b)]*OA +[a/(a+b)]OB

but i don't know how to use this equation in this case..i really don't know how to get started T-T
 
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I'm not sure I understand, ED < EC so how can the ratio be 3:2?? I am familiar with external division of a point but are you sure that is it?
 

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