1. The problem statement, all variables and given/known data A 10.0 microfarad capacitor is charged by a 10.0 V battery through a resistance R. The capacitor reaches a potential difference of 4.00 V in a time interval of 3.00 s after charging begins. Find R. 2. Relevant equations 3. The attempt at a solution So basically i got an answer of 587314 ohms..which is kinda a large number...but i don't know the right answer. So what I did was that i used the formula: emf - potential difference capacitor - IR = 0. Then i plugged in the values for the emf and the p.d. capacitor, which gave me 6. Then for the IR part, i plugged in the current as a function of time formula for charging in the 'I' spot and then simply plugged in the R value from the data. Then after calculating, I 'ln' both sides and solved for R...to me, it makes sense, but that's just me..could anyone help me confirm whether the steps i'm doing is correct or even better if they got the same answer as me...??