RC Circuits: Calculating Voltage

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To calculate the time 't' for the voltage across a capacitor array (Vc) to reach 80% of the initial voltage (Vo), the relevant equations are Vc = Vo (1 - e^[-(t/tau)]) and tau = R.C. The ratio Vc/Vo at 80% is 0.8, which simplifies the equation to 0.8 = 1 - e^[-(t/tau)]. Rearranging this gives e^[-(t/tau)] = 0.2, leading to t = -tau * ln(0.2). The final expression for 't' can be derived in terms of the resistances and capacitances involved.
rickstar008
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I've been trying to answer the following equation but I just can't get my head around it!

'calculate the time taken 't' for the voltage over capacitor array (Vc) to reach 80% of Vo, in terms of Vo, R, C1 and C2 (caps are in parallel)'



I know I need these two equations but I just don't know what to do with them:
Vc = Vo (1 - e^[-(t/tau)])
tau = R.C



I have tried solving it but I just doesn't make sense and there isn't an RC circuit calculator that I can check my answer with :(, anyways help would be fantastic, thanks
 
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What is Vc/Vo when Vc reaches 80% of Vo?
 
Hi there, in this part of the question, the values of Vc and Vo aren't given so I'm not too sure where to go from there
 
No matter what the actual value of Vc is, the ratio Vc/Vo is...?
 
oooops sorry, the exact question I have is:

1) Consider the circuit in fig. 1
a) Derive the expression for the time taken for the p.d., Vc, across the capacitor array to reach 80% of Vo in terms of C1, C2, R and Vo
 
rickstar008 said:
oooops sorry, the exact question I have is:

1) Consider the circuit in fig. 1
a) Derive the expression for the time taken for the p.d., Vc, across the capacitor array to reach 80% of Vo in terms of C1, C2, R and Vo

And again I ask you to consider what the statement "Vc across the capacitor array to reach 80% of Vo" implies for the ratio Vc/Vo.
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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