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Determining the capacitor value for an RC circuit

  1. Oct 3, 2016 #1
    • OP warned about not using the homework template
    hi, i have a question which i was hoping someone could help with,


    a series circuit featuring a capacitor (C) charging via a 1Mohm (R) resistor and a 12volt dc supply(VS).


    i know the equation to describe VC is VC=VS(1-e -t/RC)


    the question is: assuming VC is 2V after a time of 4 seconds, determine approximate value of the capacitor.


    i have rearranged the equation to C= -t / Rloge(1-VC/VS).


    i have calculated it as follows: 2/12= 0.166, then 1 - 0.166= 0.834.

    loge0.834= 2.267

    1000000 x 2.267 = 2267047

    4/2267047 = 0.0000017644uf


    please could some one help with the calculation.


    regards


    matt.
     
  2. jcsd
  3. Oct 3, 2016 #2

    gneill

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    Your value for the natural log of 0.834 doesn't look right. Check: the log of a value less than one should be negative.
     
  4. Oct 3, 2016 #3

    phyzguy

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    I think you've done the calculation correctly, but how did you deal with the units? You have a time in seconds divided by a resistance in Ohms, so what are the units of your answer?

    Oops, I missed gneill's point. You need to correct that as well.
     
  5. Oct 3, 2016 #4

    gneill

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    I've changed your thread title to better describe the problem. Too vague or general titles are frowned upon :smile:
     
  6. Oct 3, 2016 #5

    kuruman

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    This is not correct. I suggest that you solve this problem algebraically and substitute at the very end. It will be much easier to troubleshoot your work if you do that.
     
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