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Solve RC Impulse Response: Voltage @ a RC Circuit
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[QUOTE="Frank-95, post: 5359023, member: 570310"] Hello. I would need some clarifications about the impulse response of a RC circuit. [B] 1. Homework Statement [/B] Find the impulse response relative to the [B]v[SUB]c[/SUB](t)[/B] voltage. [ATTACH=full]184503[/ATTACH] NOTE: delta(t) is the exact dirac's delta of infinite amplitude, not an approximated peak. [h2]Homework Equations[/h2] [B]δ(t) = d θ(t) / dt[/B] [h2]The Attempt at a Solution[/h2] First of all I have a doubt of theoretical nature. If we know that capacitor's voltage is a continuous function ([B]v[SUB]c[/SUB](0[SUP]-[/SUP]) = v[SUB]c[/SUB](0[SUP]+[/SUP][/B]), and know that [B]v[SUB]c[/SUB] = 0[/B] for [B]t < 0[/B], how can voltage change? Shouldn't it remain 0 for the impulse duration, considering the circuit completely ideal? Anyway, is it correct to consider the impulse source as a step one, and then derivate the function? Specifically talking, I found the Thevenin equivalent between a and b, and it comes out: [B]R[SUB]th[/SUB] = 1,6344 Ω V[SUB]th[/SUB] = -0.3313 V[/B] Then I calculate the step response as: [B]v[SUB]c[SUB]θ[/SUB][/SUB](t) = -0.3323 θ(t) (1 - e[SUP]-t/1.6344[/SUP])[/B] From here is it correct to just derivate this function to get the impulse response? [B]v[SUB]c[SUB]δ[/SUB][/SUB](t) = -0.3323/1.6344 e[SUP]-t/1.6344[/SUP] [/B] Thank you very much. [/QUOTE]
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Solve RC Impulse Response: Voltage @ a RC Circuit
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