- #1

- 465

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show that [itex]\frac{d\hat{r}}{dt}[/itex]=[itex]\hat{θ}[/itex][itex]\dot{θ}[/itex]

also, [itex]\frac{d\hat{θ}}{dt}[/itex]=-[itex]\dot{θ}[/itex]r

i've tried finding the relationship between r and theta via turning it into Cartesian coord.s, and i've tried the S=theta r but still no luck.

S=theta r

dS/dt=d(theta)/dt r which is similar to the RHS of the second equation i'm supposed to show. but i don't know how to turn dS/dt into dtheta hat /dt