Reaction of strontium nitrate + copper (II) sulfate pentachloride?

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Discussion Overview

The discussion revolves around the chemical reaction between strontium nitrate and copper (II) sulfate pentahydrate, specifically focusing on the balanced chemical equation and the calculation of theoretical yield in a laboratory setting.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant presents a balanced chemical equation for the reaction but expresses uncertainty about including the pentahydrate component in the equation.
  • Another participant suggests that the molar mass of copper sulfate should include the pentahydrate part and recommends writing a net ionic reaction to simplify the process.
  • A later reply clarifies the correct form of copper in solution and mentions that copper nitrate will also be hydrated, suggesting consulting a handbook for details.
  • The original poster later corrects their terminology to "pentahydrate" and proposes a revised equation that includes water, along with calculations for moles and theoretical yield.
  • Participants discuss the approach to finding the limiting reagent and calculating the percentage yield based on experimental results.

Areas of Agreement / Disagreement

Participants generally agree on the approach to the problem, but there are varying levels of certainty regarding the details of the chemical species involved and the calculations required. No consensus is reached on the final correctness of the calculations or the balanced equation.

Contextual Notes

There are unresolved aspects regarding the hydration states of the compounds and the implications for the balanced equation. The discussion also highlights the complexity of the reaction and the need for careful consideration of stoichiometry.

Who May Find This Useful

This discussion may be useful for students working on similar chemistry lab assignments, particularly those involving precipitation reactions and stoichiometric calculations.

sarcasma
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Homework Statement


We are doing a lab where we react 2.00 g of strontium nitrate (dissolved in water) + 2.00 g of copper (II) sulfate pentahydrate (dissolved in water). I need to make sure that I did the balanced chemical equation right?
we eventually have to find the theoretical yield.

The Attempt at a Solution


Sr(NO3)2 (aq) + CuSO4(aq) -> SrSO4(s) + CU(NO3)2 (aq)

I'm not sure if i put the pentahydrate (5H2O) into the equation because I'm not sure where it goes, but i think i have to because the 2.00 g of copper (II) sulfate pentahydrate is partially H20?
 
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Seems like you are on the right track, although I am not sure if I have ever heard about copper (II) sulfate pentachloride :wink:

When calculating moles of copper sulfate you have to incorporate pentahydrate part into molar mass.

Try to write net ionic reaction, you will get rid of the copper then.

Copper is a little bit tricky here, as in the solution it is not present in the form of pentaaqua complex, but rather hexaaqua, which means that it reacts with water when dissolved. To make things more complicated copper nitrate solid will be hydrated as well, but for details you should consult some handbook. Net ionic reaction allows you to ignore all these problems.
 
oops i meant pentahydrate, haha sorry, i edited it. :)

will it be just ok if i use this equation, since that looks really complicated and I'm not really dealing with the other stuff, just the precipitate SrSO4

Sr(NO3)2 (aq) + CuSO4.5(H2O) (aq) -> SrSO4(s) + Cu(NO3)2 (aq) + 5(H2O)

then i would
1. find the mol for Sr(NO3)2 and CuSO4.5(H2O)-> 0.009450 mol and 0.008009 mol
2. find the limiting reagent-> CuSO4.5(H2O)
3.use ratios to find the theoretical yield for SrSO4 -> 1.471 g
4. percentage yield, i got 1.41 g in my experiment, so -> 95.9%

would this be right?
 
alright, thanks for the help !
 

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