- #1

a) A\B = (U\B)\(U\A)

To do this, show it both ways.

1) A\B contains (U\B)\(U\A)

2) (U\B)\(U\A) contains A\B

I'll start with 2)

if x is in (U\B)\(U\A),

then

**x is in (U\B) and x is NOT in (U\A).**

then

**(x is in U and x is NOT in B) and (x is NOT in U and x is in A)**

so,

**x is in U and x is NOT in U and x is NOT in B and x is in A**

*I think i made a mistake

**"x is in U and x is NOT in U"**doesnt make sense? Any ideas?

Back at 1)

if x is in A/B,

then

**x is in A and x is NOT in B**

then

**either x is in B or x is NOT in A**

*this is where im lost :S

Anyone have any ideas on how to solve this?

Thanks in advance