Net force on 3 kg object sliding 0.4 m down an incline in 0.25 s

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Say an object of

mass = 3kg

moves down an INCLINE of a

distance = 0.4 m
In a time = .25 sec

What is the NET Force acting on the object?

I think I'm going about this with the right equations and what not...but I want to make sure...

Thanks!
 
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Well first you have to calculate the acceleration then apply to Newton's second law F=ma.
 
binahkitty said:
Say an object of

mass = 3kg

moves down an INCLINE of a

distance = 0.4 m
In a time = .25 sec

What is the NET Force acting on the object?
What is the speed at time t=0? Is it at rest?

AM
 
Assuming it starts at rest and assuming it's uniform acceleration, the acceleration would be obtained from the equation x = x0 + vt + 0.5a*t^2 (apologies, I don't know the board code for making pretty equations just yet, this is my first post). Then, as Kurdt said, you can use F = ma to work out the net force on the object. :smile:
 
binahkitty said:
I think I'm going about this with the right equations and what not...but I want to make sure...
Where's your working then?

:rolleyes: