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Rearrangement of spring equations not making sense

  1. Aug 20, 2013 #1
    Hello All,
    Something that has bugged me as I have been working through my Physics notes is the statement:

    angular frequency for a spring: ω=2πf AND f=√(ω/2π)

    It seems to me that simply rearranging the angular frequency equation would give f=ω/2π.
    I am confused as to where the square root is coming from.

    Thanks for any clarification anyone can provide.
     
  2. jcsd
  3. Aug 20, 2013 #2
    There must be something wrong with your notes!! ω does equal 2∏f and therefore f = 2∏/ω
     
  4. Aug 21, 2013 #3
    Maybe you got it confused with the simple harmonic motion eq: [itex]\omega = \sqrt{K/M}[/itex] ?
     
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