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Rearranging an equation, It includes a square root.

  1. Jan 21, 2009 #1
    I want to find the value of r such that:

    sqrt[(r^2)+(110^2)] + r = 160

    Is there a way of doing it?

    I have found a solution through trial and error (1dp). But I want a method of finding an exact answer.

    Thanks
     
  2. jcsd
  3. Jan 21, 2009 #2
    I just found the solution:

    r = (675/16) using an online equation solver.

    But how do I get to that? Without trial and error?
     
  4. Jan 21, 2009 #3
    Doesn't matter anymore, I figured it out:

    sqrt(r²+110²) = 160 -r

    r² + 110² = (160 - r)²
    r² + 110² = 160² - 2*160*r +r²
    320r = 160²-110²
    r = 13500/320 = 42.1875
     
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