Rearranging equation into another form.

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Homework Help Overview

The discussion revolves around rearranging a transfer function related to circuit analysis. The original poster presents a transfer function involving resistances (R1, R2) and capacitances (C1, C2) and seeks to transform it into a different form.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to manipulate the transfer function by multiplying the numerator and denominator by various terms but has not yet succeeded. Some participants question the relationship between capacitances and resistances, particularly considering the implications of setting C1 to zero.

Discussion Status

Participants are exploring the implications of the variables involved and questioning the assumptions about the relationships between resistances and capacitances. There is an acknowledgment of potential discrepancies in the equations presented, indicating a productive direction in the discussion.

Contextual Notes

There is a mention of non-zero constraints for the capacitances and resistances, and a suggestion that the circuit diagram may be necessary for further clarity, though it is not provided.

Sherry Darlin
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Homework Statement


I have a transfer function as part of a circuit analysis question which I obtained as:

[itex]-{\frac {{\it R2}}{ \left( {\it sC1}\,{\it R1}+1 \right) \left( {\it <br /> R2}\,{\it sC2}+1 \right) }}[/itex]

Which needs to be turned into:

asd.jpg


The Attempt at a Solution



I have attempted by multiplying the top and bottom of the fraction by R1, s, C1, etc, trying to manipulate to get into the required form, but no luck yet.
 
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Are C's and R's related in any way?

Suppose you set C1 = 0. Then the first expression is finite whereas the second one is zero.
 
clamtrox said:
Are C's and R's related in any way?

Suppose you set C1 = 0. Then the first expression is finite whereas the second one is zero.


C stands for the capacitance, and R is the resistance.

I guess I should have said C and R are non-zero. I would put the circuit diagram, but it wouldn't make sense unless you can understand it, although it's pretty easy.

I'm not sure what you mean by are they related. It's like having an equation in x and y.

Thanks for your response.
 
Sherry Darlin said:
C stands for the capacitance, and R is the resistance.

I guess I should have said C and R are non-zero. I would put the circuit diagram, but it wouldn't make sense unless you can understand it, although it's pretty easy.

I'm not sure what you mean by are they related. It's like having an equation in x and y.

Thanks for your response.

If s, R and C are independent, then there is a typo somewhere, as the two equations are not always equal.
 

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