Rearranging Formulas for Orbital Velocity and Radius

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Homework Help Overview

The discussion revolves around rearranging formulas related to orbital velocity and radius, specifically involving the equations that link the speed of a planet to the mass of a star and its orbital radius.

Discussion Character

  • Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants explore the combination of equations to express velocity in terms of other variables, questioning the correctness of their algebraic manipulations. There is discussion on how to rearrange the resulting equation to isolate the radius.

Discussion Status

The discussion is active with participants providing feedback on each other's algebraic steps. Some guidance has been offered regarding the rearrangement of the equation, but there is still uncertainty about the correct approach to isolate the variable r.

Contextual Notes

Participants express confusion regarding the manipulation of square roots and the implications of multiplying or dividing terms in the equations. There is an acknowledgment of the need to clarify the algebraic steps involved in the rearrangement process.

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Homework Statement



(i)
Combine Equations A and B to give a single equation for v and substitute this in place of v in Equation C.
(ii)
Rearrange your answer to part (i) to make r the subject of the equation.

Homework Equations



Equation A
z = Δλ/λ0

Equation B
v = zc

For a planet such as the one orbiting Gliese, the speed v is linked to the mass of the star M and the planet’s orbital radius, by Equation C:

Equation C
v2 = GM/r

G is Newton’s universal constant of gravitation.

The Attempt at a Solution



(i) v = (Δλ/λ0)c -> (Δλ/λ0)c2 = GM/r
(ii) this is where I'm not sure, is the above correct? I always get roots confused.
 
Last edited:
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Are you sure about your result for v^2 in equ. (i)?
It looks like you only squared part of your expression for v.
 
((Δλ/λ0)c)2 = GM/r
 
That looks good to me, now they ask you to rearrange your expression
to make r the subject of the equation. Shall we interpret this to mean solving for r ?
 
Last edited:
((Δλ/λ0)c)2 = GM/r

So do I multiply the r to both sides now or remove the root?

(Δλ/λ0)c = √(GM/r) or ((Δλ/λ0)c)2/r = GM
 
Last edited:
what are you solving for? that will help you decide which direction to take.
 
I'm trying to make r the subject.

((Δλ/λ0)c)2/r = GM

r = ((Δλ/λ0)c)2xGM
 
Your algebra doesn't look quite right.
To this expression: ((Δλ/λ0)c)2 = GM/r

are you sure you multiplied both sides by r ??
 
((Δλ/λ0)c)2 = GM/r

((Δλ/λ0)c)2 x r = GM

totally not sure
 
  • #10
Looks good, you're almost there now.
 
  • #11
so then:

r = GM/((Δλ/λ0)c)2
 
  • #12
well done :approve:
 

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