Rearranging the Friedmann Equation

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Homework Help Overview

The discussion revolves around rearranging the Friedmann equation to find the present age of the universe, assuming a flat universe with both matter and a cosmological constant. Participants are attempting to rewrite the equation in a specific format involving the Hubble parameter and energy density ratios.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are discussing how to manipulate the Friedmann equation to achieve the desired format. There are attempts to factor out terms and clarify the meaning of certain variables, such as the difference between critical density and current density. Questions arise regarding the mathematical expression of a flat universe and the implications of energy density scaling.

Discussion Status

Some participants have provided hints and clarifications regarding the definitions of variables and the mathematical expressions involved. There is ongoing exploration of the relationships between different terms in the equation, but no consensus has been reached on the final steps or justifications needed for the integration process.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is a focus on understanding the implications of the cosmological constant and the scaling of energy densities with respect to the scale factor.

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Homework Statement


Assume that the universe today is flat with both matter and a cosmological constant, the latter with energy density which remains constant with time. Integrate Eq. (1.2) to find the present age of the universe. That is, rewrite Eq. (1.2) as:

dt = H0-1 da / a [ΩΛ + (1 - ΩΛ ) / a3 ]-1/2

where ΩΛ is the ratio of energy density in the cosmological constant to the critical density.

Homework Equations


[/B]
Equation 1.2:

H2(t) = 8πG/3 [ρ(t) + (ρcr - ρ0) / a2(t)]

ρcr ≡ 3H02 / 8πG

The Attempt at a Solution


I'm having a little difficulty getting equation 1.2 into the format desired above. My idea was to factor out a ρcr from the right hand side, which leads me to the following:

H2(t) = 8πG/3 * ρcr [ρ(t)/ρcr + (ρcr - ρ0) / a2(t)*ρcr]

= 8πG/3 * (3H02/8πG) [ρ(t)/ρcr + (ρcr - ρ0) / a2(t)*ρcr]

= H02 [ρ(t)/ρcr + (ρcr - ρ0) / a2(t)*ρcr]

At this point, I run into a little difficulty switching things up inside the brackets like I need to.

Using some things I've gleaned from various sources online, I've come to the following idea:

ρ(t)/ρcr = Ω

Where Ω = Ωmatter + ΩΛ

I'm not really quite sure what the difference ρcr - ρ0 is supposed to represent, so my last step looks like the following:

H2(t) = H02 [Ω + 1 / a2 - ρ0 / (ρcr * a2)]Without actually telling me what to do, could someone provide a hint as to what I may be missing? Thank you very much.
 
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TRB8985 said:

Homework Statement


Assume that the universe today is flat with both matter and a cosmological constant, the latter with energy density which remains constant with time. Integrate Eq. (1.2) to find the present age of the universe. That is, rewrite Eq. (1.2) as:

dt = H0-1 da / a [ΩΛ + (1 - ΩΛ ) / a3 ]-1/2

where ΩΛ is the ratio of energy density in the cosmological constant to the critical density.

Homework Equations


[/B]
Equation 1.2:

H2(t) = 8πG/3 [ρ(t) + (ρcr - ρ0) / a2(t)]

ρcr ≡ 3H02 / 8πG

The Attempt at a Solution


I'm having a little difficulty getting equation 1.2 into the format desired above. My idea was to factor out a ρcr from the right hand side, which leads me to the following:

H2(t) = 8πG/3 * ρcr [ρ(t)/ρcr + (ρcr - ρ0) / a2(t)*ρcr]

= 8πG/3 * (3H02/8πG) [ρ(t)/ρcr + (ρcr - ρ0) / a2(t)*ρcr]

= H02 [ρ(t)/ρcr + (ρcr - ρ0) / a2(t)*ρcr]

At this point, I run into a little difficulty switching things up inside the brackets like I need to.

Using some things I've gleaned from various sources online, I've come to the following idea:

ρ(t)/ρcr = Ω

Where Ω = Ωmatter + ΩΛ

I'm not really quite sure what the difference ρcr - ρ0 is supposed to represent, so my last step looks like the following:

H2(t) = H02 [Ω + 1 / a2 - ρ0 / (ρcr * a2)]Without actually telling me what to do, could someone provide a hint as to what I may be missing? Thank you very much.
Do you know the definition of H(t)? How does it relate to the scale factor a(t) ?
 
TRB8985 said:

Homework Statement


Assume that the universe today is flat with both matter and a cosmological constant, the latter with energy density which remains constant with time.

##\rho_0## is ##\rho\left( t \right)## evaluated at ##t = t_0 = t_{\mathrm{now}}##. Since ##\rho\left( t \right) = \rho_m \left( t \right) + \rho_\Lambda \left( t \right)##, ##\rho_0 = \rho_m \left( t_0 \right) + \rho_\Lambda \left( t_0 \right)##, and ##\rho_\Lambda \left( t_0 \right) = \rho_\Lambda \left( t \right)##, since ##\rho_\Lambda## is constant.

Adding to what @nrqed asked, how is "the universe today is flat" expressed mathematically?
 
Good evening nrqed and George, thank you for your hints.

I think I've come to the answer to this problem with your help, but I'm not sure if I'm skipping some justifications or not.

Given what you said George, "the universe today is flat" ⇒ ρ0 / ρcr = Ω0 = 1.

Continuing from where I left off in my first post, and using the definition of H(t) as you suggested nrqed, here's what I have:

[(da/dt)/a]^2 = H02 [Ω(t) + 1 / a2(t) - 1/ a2(t)]

= H02 [Ω(t)]

= H02m(t) + ΩΛ]

= H02 [(1 - ΩΛ)/a3 + ΩΛ]

On page 4 of the Modern Cosmology textbook, Dodelson writes ".. the energy density of matter scales as a-3". So hence, I figured slapping that a-3 below (1 - ΩΛ) was justified by those words. (That, and I don't see any other way to get an a-3 in the expression to match what I need.)

If this process is correct, I'll have absolutely no problem separating the variables and integrating for the next part. I just don't know if that last step is okay.
 

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