Baluncore said:
Yes. But for analysis of Q, the diagram in post #24 is labelled backwards with source and load.
It does not matter if the circulating energy in a resonator is increasing or decaying, it will take Q cycles to increase or decrease to within 4% of the final amplitude.
Most of the time it does not matter if it is a receiver or a transmitter being analysed. If it is a high power transmitter you must impedance match better for the frequency being transmitted, or components will be destroyed.Correct.
It's getting clearer now. So in summary, if consider
our circuit modeled by picture in #24 after swapping
right with left side, so consisting of tuned circuit
as "source" with impedadance Z_S= X_S + i Y_S and
the antenna as "load" with impedance Z_L= X_L+i Y_L .
Finally, what is the essential role of the coupling capacitor?
How I understand it so far:
As you explained in #20 we want our circuit to be selective, so
formally can we archieve it if we make Q of the source
high, right? So we have to do something with our load.
Ok, then as far as I understand it correctly, we do it by adding a capacitor in series to the antenna aka load.
We obtain now a new "load" consisting of antenna + this capacitor, and therefore we obtain new load impedance Z_L= X_L+i Y_L simply as sum of the impedance of old load (=the antenna alone) +
the impedance of this coupling capacitor as "new modification".
Are my reasonings correct up to now?
Next, in A1 you wrote the mathematical conditions which we want to archieve by adding this capacitor. We want that the load is more than Q times the resonant reactance;
As far as I interstand it correctly, the "reconant reactance" is Y_S, ie the reactance of the source
(=tuned circuit), right?
The "load", what is it in terms of
Z_L, X_L, Y_L?