Understanding the Derivation of Reciprocal Lattice Basis from Equations 5 and 6

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SUMMARY

The discussion focuses on deriving the reciprocal lattice basis vectors \( b_i \) from the equations \( a_i \) using linear independence and orthogonality principles. Specifically, it highlights that the equations \( b_i \cdot a_j = 2\pi \delta_{ij} \) provide unique solutions for \( b_i \). The derivation process involves expressing \( b_1 \) as \( c_1 (a_2 \times a_3) \) and solving for the constant \( c_1 \) using the equation \( a_1 \cdot b_1 = 2\pi \). This method ensures that the derived vectors satisfy the necessary conditions for reciprocal lattice vectors.

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  • Understanding of vector algebra and linear independence
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  • Knowledge of reciprocal lattice concepts in crystallography
  • Basic grasp of delta functions and their applications in physics
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Students and researchers in physics, particularly those focusing on crystallography, solid-state physics, and materials science, will benefit from this discussion. It is also valuable for anyone looking to deepen their understanding of reciprocal lattice concepts and their derivation.

sam45
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I am trying to understand how to determine the reciprocal lattice basis from the lattice basis vectors
may someone explain to me or show me the steps of how equations 7a, 7b, 7c were determined from equations 5 and 6
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You can check directly that those formulas for the ##b_i## satisfy the equations that you want. For example, ##b_1\cdot a_1=2\pi\frac{a_1\cdot (a_2\times a_3)}{a_1\cdot (a_2\times a_3)}=2\pi##.

Since the vectors ##a_i## are linearly independent, the equations ##b_i\cdot a_j=2\pi\delta_{ij}## can be uniquely solved for the ##b_i##, and hence the above are the unique solutions.

If you wanted to figure out these formulas from scratch, you could argue like this: since ##b_1## is orthogonal to both ##a_2## and ##a_3##, you know that ##b_1=c_1 (a_2\times a_3)## for some constant ##c_1##. Then the equation ##a_1\cdot b_1=2\pi## let's you solve for ##c_1##, etc.
 
hello,

thank you. yes, but my question is how are they solved for bi i.e. what are the steps to find b1 for example

thank you
 
See the last paragraph of my post
Infrared said:
If you wanted to figure out these formulas from scratch, you could argue like this: since ##b_1## is orthogonal to both ##a_2## and ##a_3##, you know that ##b_1=c_1 (a_2\times a_3)## for some constant ##c_1##. Then the equation ##a_1\cdot b_1=2\pi## let's you solve for ##c_1##, etc.
 
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thank you for your help!
 

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