Reducing the Wave Equation: Change of Variables

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Homework Help Overview

The discussion revolves around the wave equation \( u_{tt}-\alpha^{2}u_{xx}=0 \) and the attempt to reduce it to the form \( \phi_{\xi \eta}=0 \) using the change of variables \( \xi=x-\alpha t \) and \( \eta=x+\alpha t \). Participants are exploring the implications of this transformation and the resulting expressions.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the application of the chain rule in deriving the second partial derivatives and question the consistency of variable usage between \( u \) and \( \phi \). There are inquiries about the absence of mixed partial derivatives in the calculations and the implications of this on the solution process.

Discussion Status

The discussion is ongoing, with some participants providing guidance on the correct application of differentiation rules and raising concerns about the clarity of variable definitions. There is no explicit consensus, but suggestions for reevaluation and clarification are present.

Contextual Notes

Some participants express confusion regarding the treatment of variables and the potential for errors in the differentiation process. The original poster indicates a possible misunderstanding in their approach, which may be common among students tackling this type of problem.

K29
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Homework Statement



Show that the wave equation [itex]u_{tt}-\alpha^{2}u_{xx}=0[/itex] can be reduced to the form [itex]\phi_{\xi \eta}=0[/itex] by the change of variables
[itex]\xi=x-\alpha t[/itex]
[itex]\eta=x+\alpha t[/itex]

The Attempt at a Solution



[itex]\frac{\partial u}{\partial t}=\frac{\partial \xi}{\partial t}\frac{\partial \phi}{\partial \xi}+\frac{\partial \eta}{\partial t}\frac{\partial \phi}{\partial \eta}[/itex] (chain rule)
[itex]\frac{\partial^{2} u}{\partial t^{2}}=\frac{\partial}{\partial t}(\frac{\partial \xi}{\partial t}\frac{\partial \phi}{\partial \xi} + \frac{\partial \eta}{\partial t} \frac{\partial \phi}{\partial \eta})[/itex]
After some use of chain rule and product rule I get:
[itex]\frac{\partial^{2} u}{\partial t^{2}}= \frac{\partial^{2}\xi}{\partial t^{2}}\frac{\partial\phi}{\partial\xi} + \left(\frac{\partial \xi}{\partial t}\right)^{2} \frac{\partial^{2}\phi}{\partial \xi^{2}} + \frac{\partial^{2}\eta}{\partial t^{2}}\frac{\partial\phi}{\partial\eta} + \left(\frac{\partial \eta}{\partial t}\right)^{2} \frac{\partial^{2}\phi}{\partial \eta^{2}}[/itex] (1)
Similarly
[itex]\frac{\partial^{2} u}{\partial x^{2}}=\frac{\partial^{2}\xi}{\partial x^{2}}\frac{\partial\phi}{\partial\xi} + \left(\frac{\partial \xi}{\partial x}\right)^{2}\frac{\partial^{2}\phi}{\partial \xi^{2}}+\frac{\partial^{2}\eta}{\partial x^{2}}\frac{\partial\phi}{\partial\eta} + \left(\frac{\partial \eta}{\partial x}\right)^{2}\frac{\partial^{2}\phi}{\partial \eta^{2}}[/itex] (2)
Making the substitutions:
[itex]\frac{\partial \xi}{\partial t}=-\alpha[/itex], [itex]\frac{\partial^{2}\xi}{\partial t^{2}}=0[/itex]
[itex]\frac{\partial \xi}{\partial x}=1[/itex], [itex]\frac{\partial^{2}\xi}{\partial x^{2}}=0[/itex]
and
[itex]\frac{\partial \eta}{\partial t}=\alpha[/itex], [itex]\frac{\partial^{2}\xi}{\partial t^{2}}=0[/itex]
[itex]\frac{\partial \eta}{\partial x}=1[/itex], [itex]\frac{\partial^{2}\xi}{\partial x^{2}}=0[/itex]

Substituting these into (1) and (2) and substituting (1) and (2) into the original wave equation we get:
[itex]\alpha^{2}\frac{\partial^{2}\phi}{\partial \xi^{2}}+\alpha^{2}\frac{\partial^{2} \phi}{\partial \eta^{2}}-\alpha^{2}\left(\frac{\partial^{2}\phi}{\partial \xi^{2}}+\frac{\partial^{2}\phi}{\partial\eta^{2}}\right)=0[/itex]

[itex]0=0[/itex]

Has something gone wrong here? Please help. Thanks
 
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Hi K29! :wink:

I don't follow this. :confused:

First, u is not necessarily equal to φ … keep with u until the end!

Second, you seem to have used the chain rule for ∂/∂t (and ∂/∂x) the first time, but not for the second time (which you haven't copied)

Start again. :smile:
 
K29 said:

Homework Statement



Show that the wave equation [itex]u_{tt}-\alpha^{2}u_{xx}=0[/itex] can be reduced to the form [itex]\phi_{\xi \eta}=0[/itex] by the change of variables
[itex]\xi=x-\alpha t[/itex]
[itex]\eta=x+\alpha t[/itex]


The Attempt at a Solution



[itex]\frac{\partial u}{\partial t}=\frac{\partial \xi}{\partial t}\frac{\partial \phi}{\partial \xi}+\frac{\partial \eta}{\partial t}\frac{\partial \phi}{\partial \eta}[/itex] (chain rule)
[itex]\frac{\partial^{2} u}{\partial t^{2}}=\frac{\partial}{\partial t}(\frac{\partial \xi}{\partial t}\frac{\partial \phi}{\partial \xi} + \frac{\partial \eta}{\partial t} \frac{\partial \phi}{\partial \eta})[/itex]
After some use of chain rule and product rule I get:
[itex]\frac{\partial^{2} u}{\partial t^{2}}= \frac{\partial^{2}\xi}{\partial t^{2}}\frac{\partial\phi}{\partial\xi} + \left(\frac{\partial \xi}{\partial t}\right)^{2} \frac{\partial^{2}\phi}{\partial \xi^{2}} + \frac{\partial^{2}\eta}{\partial t^{2}}\frac{\partial\phi}{\partial\eta} + \left(\frac{\partial \eta}{\partial t}\right)^{2} \frac{\partial^{2}\phi}{\partial \eta^{2}}[/itex] (1)
Similarly
[itex]\frac{\partial^{2} u}{\partial x^{2}}=\frac{\partial^{2}\xi}{\partial x^{2}}\frac{\partial\phi}{\partial\xi} + \left(\frac{\partial \xi}{\partial x}\right)^{2}\frac{\partial^{2}\phi}{\partial \xi^{2}}+\frac{\partial^{2}\eta}{\partial x^{2}}\frac{\partial\phi}{\partial\eta} + \left(\frac{\partial \eta}{\partial x}\right)^{2}\frac{\partial^{2}\phi}{\partial \eta^{2}}[/itex] (2)
Making the substitutions:
[itex]\frac{\partial \xi}{\partial t}=-\alpha[/itex], [itex]\frac{\partial^{2}\xi}{\partial t^{2}}=0[/itex]
[itex]\frac{\partial \xi}{\partial x}=1[/itex], [itex]\frac{\partial^{2}\xi}{\partial x^{2}}=0[/itex]
and
[itex]\frac{\partial \eta}{\partial t}=\alpha[/itex], [itex]\frac{\partial^{2}\xi}{\partial t^{2}}=0[/itex]
[itex]\frac{\partial \eta}{\partial x}=1[/itex], [itex]\frac{\partial^{2}\xi}{\partial x^{2}}=0[/itex]

Substituting these into (1) and (2) and substituting (1) and (2) into the original wave equation we get:
[itex]\alpha^{2}\frac{\partial^{2}\phi}{\partial \xi^{2}}+\alpha^{2}\frac{\partial^{2} \phi}{\partial \eta^{2}}-\alpha^{2}\left(\frac{\partial^{2}\phi}{\partial \xi^{2}}+\frac{\partial^{2}\phi}{\partial\eta^{2}}\right)=0[/itex]

[itex]0=0[/itex]

Has something gone wrong here? Please help. Thanks

How come you not getting any mixed-partials in there. I don't see a single one. Gonna' need some right? I think I know what the problem is but not sure but it's one that gets lots of students and also, I don't know about you but that phi thing just gets in the way for me. Isn't it really just:

[tex]\frac{\partial u}{\partial t}=\frac{\partial u}{\partial \xi} \frac{\partial \xi}{\partial t}+\frac{\partial u}{\partial \eta} \frac{\partial \eta}{\partial t}[/tex]

Now when you do the second partial you get terms like:

[tex]\frac{\partial}{\partial t}\left(\frac{\partial u}{\partial \xi}\right)[/tex]

What exactly is that?
 
Thanks for the help. Solved :)
 

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