Reduction of quaternary ammonium salt

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Discussion Overview

The discussion revolves around the reduction of quaternary ammonium salts, specifically focusing on the behavior of the -NMe3 group during various reduction reactions. Participants explore different reducing agents and their effects on the compound, as well as the potential products formed from these reactions.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant expresses confusion regarding the reduction of the quaternary ammonium salt Ph-CH2-CH2-N^+Me3 with Zn-Hg in HCl, noting that the -NMe3 group is not disturbed according to their text.
  • The same participant questions the outcomes when using LiAlH4 or NaBH4, asking what products would result and how the reaction would proceed.
  • Another participant suggests that there may be confusion between the reduction of the cation versus the anion of the quaternary ammonium compound, implying that the identity of the anion is relevant.
  • A different participant questions whether the discussion pertains to an "acid-base" neutralization reaction, stating that there is no N+ cation in aqueous solution.
  • Another participant expresses uncertainty about quaternary ammonium compounds being good substrates for reductions, suggesting that the Me3N+ group may act as a leaving group and that elimination pathways could occur, potentially leading to products like styrene or ethylbenzene.
  • This participant also questions the appropriateness of using Wolff-Kishner or Clemmensen conditions for such compounds, speculating that the text might be indicating possible side reactions when reducing a carbonyl group in the presence of a quaternary ammonium group.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the behavior of quaternary ammonium salts during reduction, with multiple competing views and uncertainties expressed regarding the reactions and products.

Contextual Notes

There are limitations regarding the assumptions made about the identity of the anion in the quaternary ammonium compound and the conditions under which the reactions are performed. The discussion also highlights the potential for side reactions and the appropriateness of various reduction methods.

AdityaDev
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I am confused with the reduction of quaternary ammonium salt.
##Ph-CH_2-CH_2-N^+Me_3##
on reduction with Zn-Hg in HCl will not work. The -NMe3 is not disturbed(given in my text). But why?
Also the text says On reduction with LiAlH4 or NaBH4, -NMe3 would be disturbed. what would be the product? In which way will the reaction proceed?
Wolf-kishner reduction will disturb the group. But what would the final product be?
 
AdityaDev said:
reduction of quaternary ammonium salt.
Are you certain you haven't confused reduction of the anion of a quaternary ammonium compound with the cation, and omitted the identity of the anion being reduced?
 
Are you talking about an "acid-base" neutralization reaction? There is no N+ cation in aqueous solution.
 
I may be wrong, but I don't remember quaternary ammonium compounds as particularly good substrates for reductions.
The Me3N+ group looks like a leaving group to me, and that Ph in 2 may allow elimination pathways.
So, treating the compound in the OP with bases may give styrene; nucleophiles (Nu-) may give Ph-CH2-CH2-Nu (so perhaps hydride donors would give ethylbenzene? Not sure though).
In any case, I don't see why one would try Wolff-Kishner or Clemmensen conditions (normally used to reduce phenyl ketones to alkylbenzenes) on a compound like that.
Or maybe the 'text' is trying to show us that you'd have side reactions if you tried to reduce a carbonyl group on a molecule that also contains a quaternary ammonium group.
Bizarre though. :O/
 

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