Reduction of resultant Moment/Force

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SUMMARY

The discussion focuses on the calculation of resultant moment and force in a mechanical system. The user correctly calculated the resultant force (F_r) as 798.499 lb but miscalculated the distance (d) as 6.08 ft instead of the correct value of 6.57 ft from point B. The error arose from using the total force instead of the vertical component of the force in the torque formula. The correct torque equation is \(\sum M_B=\frac{3}{5}(500)(9)+6(1200)+\frac{12}{13}(260)(4)=4860 lb\cdot ft\).

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Saladsamurai
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[SOLVED] Reduction of resultant Moment/Force

So I have calculated the resultant force correctly but my solution for distance is incorrect. I keep getting 6.08 ft but the correct solution is 6.57 feet from B.
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I found [itex]F_r=798.499[/itex] which is correct. Then I used,

[tex]\sum M_B=\frac{3}{5}(500)(9)+6(1200)+\frac{12}{13}(260)(4)=4860 lb\cdot ft[/tex]

Then [itex]d=\frac{M_r}{F_r}=6.09 ft[/itex] Where is my error?
 
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F_r is the total magnitude of the resulting force, yes. But in the formula d=M/F (where M is the torque, and d is distance from axis), you want the F to be component of the total force that exerts torque. That would be the vertical component only of the total force.
 

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