Replace Loading on Frame By Single Resultant (HW Help)

[lc99]

Homework Statement

Q) Suppose that F1 = 250 lb , F2 = 90 lb , and M = 500 lb⋅ft . (Figure 1) Specify where the resultant’s line of action intersects member BC, measured from B.

Homework Equations

The Attempt at a Solution

Okay, so i am having severe problems with figuring out what i did wrong...
I am given : F1 = 250 and F2 = 90. The correct Force result is = 245 i +228 j with magnitude of 335 .
The moment given is 500 lb*ft.

I am trying to find the result's line of action that would intersect member BC measured from B. The correct answer is x = 2.34.

But, i got some other answer. I found the location of intersection with M = Fy * x (Fy because Fx would be 0 along the x-axis).

so , 500 = 228*x --> x = 2.19?? Which is wrong :(

 

[lc99]

Actually , guys, i understand what i did wrong. I had to find the sum of moments from also the forces given. I get the sum of moments from the two forces as -1033 n*m. However, the value is negative? Nevertheless, when i summed -1033 with 500 , i get -533 n*m. So, M = fy*d --> d = -533/228 = -2.34.

I got the correct answer except the value i get is negative? Is this suppose to happen or was i suppose to treat clockwise motion as Positive?