Refraction and Magnification of a Coin in a Glass Cylinder

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Homework Help Overview

The problem involves a penny placed at the bottom of a glass cylinder filled with water, exploring how refraction affects the perceived position of the coin when viewed from above. The subject area includes optics, specifically refraction and magnification.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between refraction and the apparent position of the coin, with one participant attempting to calculate a perceived distance using the refractive index of water. Others suggest sketching the situation and analyzing light rays to understand the refraction process better.

Discussion Status

The discussion has progressed with participants exploring different interpretations of how light rays behave at the water surface. Some guidance has been offered regarding sketching the situation and analyzing the angles of incidence and refraction. There is a recognition of the need to visualize the problem more clearly.

Contextual Notes

Participants note the importance of understanding the bending of light rays as they transition between different media, and there is a suggestion to consider the physical reality of observing a coin in water.

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Homework Statement



A penny is placed at the bottom of a glass cylinder that is 30 cm in height. If the cyclinder is filled to 2/5 its volume:

How much closer to an eye does the coin appear when viewed from directly above?


2. The attempt at a solution

I don't quite know how to approach this problem but since we are studying refraction, I'm guessing it has to do with it.

n water = 1.33

Can that be considered the "magnification"?

12 cm / 1.33 = 9 cm

So, it appears to be 3 cm above the bottom surface?
 
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Speedking96 said:

Homework Statement



A penny is placed at the bottom of a glass cylinder that is 30 cm in height. If the cyclinder is filled to 2/5 its volume:

How much closer to an eye does the coin appear when viewed from directly above?


2. The attempt at a solution

I don't quite know how to approach this problem but since we are studying refraction, I'm guessing it has to do with it.

n water = 1.33

Can that be considered the "magnification"?
No.

Since you are studying refraction, you should know a law that tells you how light-rays bend when they cross a surface.

Sketch the situation (bottom of glass, coin on the bottom, water surface above...)
Then sketch in two light rays coming from the coin, and headed for different points on the surface ... at the surface they refract differently: draw in the refracted rays.

Now imagine there is an eyeball looking down from above - as far as the ye is concerned, where do those rays appear to come from?
 
The rays appear to be coming from beside the coin. The coin seem stretched out.
Are they looking for a numerical answer?
 
Speedking96 said:
The rays appear to be coming from beside the coin. The coin seem stretched out.
Reality check - put a coin in a glass of water and look at it. Does it appear stretched out?

Try this: draw a dotted line through the center of the coin and perpendicular to the water surface.
Make a small angle to this line, from where it touches the coin - draw a ray for that angle.
Where the ray hits the water surface, draw in a dotted line showing the normal.
Will the ray refract away from or towards the normal (going from water to air)?

Draw in the refracted ray.
Repeat for the same small angle on the other side of the central line.

Or see:
http://www.physicstutorials.org/home/optics/refraction-of-light/apparent-depth-real-depth
 
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I've figured it out. Thank you for the link.
 
Well done.
 

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