Refractive index to measure temperature

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SUMMARY

The discussion centers on calculating the refractive index of a liquid (Liquid X) based on its temperature using the formula n = 2.25 – 0.025T. A semi-circular crown glass with a refractive index of 1.75 is used, and the critical angle for total internal reflection is determined using the formula sin(θ_c) = n2/n1. The user successfully solved the problem after receiving guidance on applying the critical angle formula.

PREREQUISITES
  • Understanding of refractive index and its relationship with temperature.
  • Knowledge of total internal reflection and critical angle calculations.
  • Familiarity with the properties of crown glass and its refractive index.
  • Basic trigonometry, specifically sine functions.
NEXT STEPS
  • Explore advanced applications of refractive index in optical engineering.
  • Learn about temperature measurement techniques using optical methods.
  • Study the principles of total internal reflection in fiber optics.
  • Investigate the effects of temperature on the refractive index of various materials.
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Students and professionals in optics, engineers working with temperature measurement systems, and anyone interested in the practical applications of refractive index in scientific and industrial contexts.

pavadrin
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Here is the question:
A factory uses a beam of light to allow workers to visually check the temperature of a liquid. A semi-circular crown glass (refractive index (n) =1.75) block is placed in a liquid X whose refractive index n changes with temperature T (in °C) according to the formula:
n = 2.25 – 0.025T
A light ray may be directed to the centre of the glass block makes and angle Ө = 60° with the normal

If the ray is totally reflected at O, find the refractive index and the corresponding temperature of liquid X.

___________________________________________​

My working:
\theta_{critical}=\frac{n_{1}}{n_{2}}
from this point onwards I am stuck, any post regarding hints/working/solution will be greatly appreciated
Thank you,
Pavadrin
 
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well, it's sin(theta_c)=n2/n1 , ( n1>n2 )

try working this out, with givens you have.
 
thank you kindly

Exotic-Matter said:
well, it's sin(theta_c)=n2/n1 , ( n1>n2 )

try working this out, with givens you have.

thanks for this bit of imformation, i have now solved the problem
 

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