(adsbygoogle = window.adsbygoogle || []).push({}); Refresh my memory plz, Inverse Trig

[tex]x=\sin^{-1}\left(-\frac{\sqrt{2}}{2}\right)[/tex]

Inverse sine is defined from [tex]-\frac{\pi}{2}[/tex] to [tex]\frac{\pi}{2}[/tex] which lies in the 1st and 4th quadrant.

So [tex]x=-\frac{\pi}{4}[/tex]

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Refresh my memory , Inverse Trig

**Physics Forums | Science Articles, Homework Help, Discussion**