Regarding current sensitivity of galvanometer

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Homework Statement



a galvanometer with 50 divisions on the scale requires a current sensitivity of 0.1 m A/division. find the galvanometer current?

Homework Equations


IS= [tex]\theta/I[/tex]

TO find the galvanometer current, i multiplied 50 with 0.1 to get the galvanometer current, as instructed by my physics teacher. my query is how this multiplication gives galvanometer current. is there any formula/

The Attempt at a Solution


 
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This literally is just the current that causes the meter to read maximum... nothing sinister.