Regarding transpose of matrix products

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Discussion Overview

The discussion revolves around the transpose of matrix products, specifically addressing a potential error in a formula presented in a linear algebra class. Participants explore the implications of transposing a product of matrices and the treatment of inverses in that context.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Homework-related

Main Points Raised

  • One participant questions the correctness of the expression (ABC-1Dt)t = DC-1BtAt, particularly why C remains inverse after transposition.
  • Another participant asserts that the correct expression should be (ABC^{-1}D^t)^t = D (C^t)^{-1} B^t A^t, suggesting the original formula is incorrect.
  • A participant expresses frustration over having written the incorrect formula on an exam, attributing it to the timing of the professor's explanation.
  • There is a mention of different notations for matrix inverses and transposes, specifically C^{-T} versus (C^{-1})^T or (C^T)^{-1}, indicating potential confusion in notation.
  • Some participants speculate that the notation might have been misread, contributing to the misunderstanding of the original expression.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correctness of the original expression. There are competing views regarding the proper treatment of the transpose and inverse in the context of matrix products.

Contextual Notes

There are unresolved questions regarding the notation used by the professor and the assumptions made about the expressions presented. The discussion highlights potential confusion stemming from different conventions in mathematical notation.

Who May Find This Useful

Students and educators in linear algebra or related fields may find this discussion relevant, particularly those grappling with matrix operations and notation conventions.

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Starting out a Lin Alg class - my prof wrote this on the board.

(ABC-1Dt)t = DC-1BtAt

On the right hand side, I get why D is D, why A and B are now both transpose, but why is C still inverse? I know the rule (D-1)t = (Dt)-1, but I do not see how the heck it applies here or what would make the original equality true.
 
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It's incorrect, it should be

[tex](ABC^{-1}D^t)^t = D (C^t)^{-1} B^t A^t[/tex]

You should ask your prof for clarification.
 
Ugh, I KNEW it was incorrect. He wrote it on the board right before we took a test - he was answering questions - so despite knowing the write answer as you put it, I wrote the wrong thing on the exam. I would have asked, but out the tests came.

This might have something to do with his being an octogenarian. Half hour late to his office hours too and forgets who the heck you are. Son of a...

Thanks for your help. Also, how do you make the script look so nice for writing math?
 
FWIW, some people write ##C^{-T}## instead of ##(C^{-1})^T## or ##(C^T)^{-1}##

Maybe you misread ##C^{-T}## as ##C^{-1}##.
 
AlephZero said:
FWIW, some people write ##C^{-T}## instead of ##(C^{-1})^T## or ##(C^T)^{-1}##

Maybe you misread ##C^{-T}## as ##C^{-1}##.

Could be - wouldn't be in keeping with his writing style though. And it wouldn't be the first mistake we've dealt with.

Thanks a bunch!
 

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