Regression for a first order system

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The discussion revolves around calculating the value of "time elapsed" using the regression equation for the diameter of a part. The equation provided is Diameter = -0.0531052 + 0.0443237 * exp(-0.0103633 * 'Time elapsed'). A specific diameter value of -0.052 is given, prompting a request for assistance in solving for time. Participants emphasize that while they won't do the calculations, they are willing to guide the user through the process, suggesting the use of the natural logarithm in the solution. The conversation highlights the importance of understanding the steps involved in solving the equation.
Smitha921
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Homework Statement


I am carrying out a regression for diameter of a part

Homework Equations



Diameter = -0.0531052 + 0.0443237 * exp (-0.0103633 * 'Time elapsed')

if diameter is -0.052
then can some one please calculate the value for time elapsed

would you please explain the steps

The Attempt at a Solution

 
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Hello @Smitha921,

:welcome:

Welcome to PF!
Smitha921 said:

Homework Statement


I am carrying out a regression for diameter of a part

Homework Equations



Diameter = -0.0531052 + 0.0443237 * exp (-0.0103633 * 'Time elapsed')

if diameter is -0.052
then can some one please calculate the value for time elapsed

would you please explain the steps

The Attempt at a Solution


We won't do your work for you. You'll have to do that yourself.

But we will try to help you along if you get stuck.

You have an equation. Solve for t. Hint: The solution involves, in part, the natural logarithm.
 
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