Related rates Balloon question. Thanks

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Homework Statement



Air is being pumped into a spherical balloon. Suppose we know the surface area of the balloon increases at a rate of 20cm^2/s when its radius is 4cm. What is the rate its volume is changing at that instant?

Homework Equations


The Attempt at a Solution



I went...

dv/dt = 4∏ (4)^2 * 20/1 = 1280∏

I know its wrong. Anyone help me out? What am i doing wrong?
 
Last edited:
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Wait no, I went:

dv/dt = (1/4pi(4)^2) *20/1

gives me 5 / 16pi