Related rates, baseball diamond

In summary: X is distance from him to third base, and z is distance from third base to where he is, when z = sqrt (90^2 + x^2)
  • #1
rocomath
1,755
1
Even problem, very please!

A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 24 ft/s.

a) At what rate is his distance from second base decreasing when he is halfway to the first base?

b) At what rate is his distance from third base increasing at the same moment?

Work for A:

Distance from each base is x, evaluate when x = 45 ft

The distance from the runner to 2nd base, is z

Using Pythagorean theorem:

[tex]2x^2=z^2[/tex]

[tex]2x\frac{dx}{dt}=z\frac{dz}{dt}[/tex]

[tex]2x\frac{dx}{dt}=x\sqrt 2\frac{dz}{dt}[/tex]

[tex]\frac{dz}{dt}\approx -34.0 ft/s[/tex]

I'm mainly concerned with the set up, same for B?
 
Physics news on Phys.org
  • #2
rocomath said:
Even problem, very please!

A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 24 ft/s.

a) At what rate is his distance from second base decreasing when he is halfway to the first base?

b) At what rate is his distance from third base increasing at the same moment?

Work for A:

Distance from each base is x, evaluate when x = 45 ft

The distance from the runner to 2nd base, is z

Using Pythagorean theorem:

[tex]2x^2=z^2[/tex]

[tex]2x\frac{dx}{dt}=z\frac{dz}{dt}[/tex]

[tex]2x\frac{dx}{dt}=x\sqrt 2\frac{dz}{dt}[/tex]

[tex]\frac{dz}{dt}\approx -34.0 ft/s[/tex]

I'm mainly concerned with the set up, same for B?

z = sqrt (90^2 + x^2)
z is your z
x is distance between him and first base

differentiate with respect to 't' .. don't know what you did

and same thing for the other base
 

What is the concept of related rates in the context of a baseball diamond?

Related rates is a mathematical concept used to analyze the changes in variables that are related to each other. In the context of a baseball diamond, it refers to the relationships between the different measurements and movements on the diamond, such as the distance between bases and the speed of the runner.

How do you set up a related rates problem for a baseball diamond?

To set up a related rates problem for a baseball diamond, you need to identify the variables involved and determine how they are related to each other. This may include using geometric formulas or equations for motion. It is also important to clearly define the initial conditions and the desired rate of change.

What are the common assumptions made when solving related rates problems for a baseball diamond?

Some common assumptions made when solving related rates problems for a baseball diamond include assuming a flat and level diamond, neglecting air resistance, and assuming the runner moves in a straight line between bases. These assumptions may not hold true in real-world scenarios, but they simplify the calculations and provide a good approximation of the actual situation.

Can related rates be used to solve practical problems in a baseball game?

Yes, related rates can be used to solve practical problems in a baseball game, such as determining the speed of a runner or the rate at which a ball is moving. By setting up and solving related rates problems, we can gain a better understanding of the underlying mathematical relationships and make predictions about the outcome of the game.

Are there any limitations to using related rates in a baseball diamond?

Like any mathematical model, there are limitations to using related rates in a baseball diamond. These include the assumptions made and the accuracy of the measurements used. Additionally, related rates may not be able to account for unexpected events or changes in the game. However, it can still provide valuable insights and predictions in many practical scenarios.

Similar threads

Replies
6
Views
601
  • Calculus and Beyond Homework Help
Replies
23
Views
933
  • Calculus and Beyond Homework Help
Replies
2
Views
238
  • Calculus and Beyond Homework Help
Replies
4
Views
1K
  • Calculus and Beyond Homework Help
Replies
12
Views
977
  • Calculus and Beyond Homework Help
Replies
1
Views
1K
  • Calculus and Beyond Homework Help
Replies
1
Views
1K
  • Calculus and Beyond Homework Help
Replies
4
Views
2K
  • Calculus and Beyond Homework Help
Replies
4
Views
1K
  • Calculus and Beyond Homework Help
Replies
2
Views
2K
Back
Top