Related Rates cylinder problem

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    Cylinder Related rates
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SUMMARY

The discussion centers on calculating the rate of change of the volume of a cylinder when both the height and base radius are expanding at 0.1 mm/min. Given the height of 250 mm and a base radius of 30 mm, the correct formula for the volume's rate of change is derived as dV/dt = π[2hr(dr/dt) + r²(dh/dt)]. The final calculated volume expansion rate is 1783 mm³/min, confirming the importance of including the π term in the equation.

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Mitchtwitchita
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A cylinder is placed in oven where both the height and base radius expand at 0.1 mm/min. When the height is 250 mm and the radius of the base 30 mm, the volume is expanding at ...mm3 /min. (Answer to nearest whole number)

r=30, h=250, dr/dh=0.1, dh/dt=0.1

dV/dt = (pi)r^2(dh/dt) + 2rh(dr/dt)
=(pi(30)^2(0.1) + 2(30)(250)(0.1)
=1783

Can anybody please show me where I'm going wrong with this one?
 
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V=\pi r^2h

You're missing a pi term!

\frac{dV}{dt}=\pi[2hr\frac{dr}{dt}+r^2\frac{dh}{dt}]
 
Thanks roco!
 

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