Related Rates - Frustum of a Cone

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Homework Help Overview

The problem involves a frustum of a cone, specifically a container being filled with water at a constant rate. The goal is to determine the rate at which the water level rises when the water is 1 metre deep.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to find a relationship between the height of the water and the radius of the frustum but is uncertain about which radius to use. They express a desire for tips on relating radius to height.
  • Some participants suggest drawing a picture to aid understanding, with one noting that viewing the frustum as a trapezoid could help establish a relationship between the dimensions.
  • There is a discussion about the effectiveness of visual aids, with mixed responses regarding their utility in solving the problem.

Discussion Status

The discussion is ongoing, with participants exploring different ways to visualize the problem and establish relationships between the variables involved. Some guidance has been offered regarding the use of a coordinate system and the trapezoid representation, but no consensus has been reached on the best approach yet.

Contextual Notes

The original poster indicates a lack of clarity on how to proceed, particularly in relating the dimensions of the frustum to the changing water level. There is also a mention of the need for a visual representation to facilitate understanding.

Temp0
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Homework Statement



A large container has the shape of a frustum of a cone with top radius 9 metres , bottom radius 2 metres , and height 7 metres. The container is being filled with water at the constant rate of 4.2 cubic meters per minute.
At what rate is the level of water rising at the instant the water is 1 metre deep?

Homework Equations


V = 1/3∏ (r^2) * h
Internet Says the volume of a frustum of a cone is V = (∏ * h / 3) (R^2 + Rr + r^2)

The Attempt at a Solution


I don't know where to start with this one, I think I have to find some relationship between the height of the cone and the radius of the cone, however, I don't know which radius to use. Once I isolate h with V, I can just derive it and substitute 4.2 for dV/dt, 1 for h, and find dh/dt. Any tips on how to relate radius to height in this situation? Thanks in advance.
 
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Have you drawn a picture?
 
Looked at from the side, a frustrum of a cone is a trapezoid. If you set up a coordinate system with origin at the center of the smaller face, then the two sides are two lines, one passing through (r, 0) and (R, h). you can write the equation for that line and so get a relation between x (the radius) and y (the height) at each point.
 
Hmm, I've tried drawing a picture, but it didn't help.

That trapezoid idea might work, i'll try it, thanks!
 
Temp0 said:
Hmm, I've tried drawing a picture, but it didn't help.
A picture by itself probably won't help, but if you draw it on a coordinate system and identify the points on the picture by their coordinates, as HallsOfIvy suggests, it will be useful.

For problems like these it's always a good idea to draw a picture, as described above.
Temp0 said:
That trapezoid idea might work, i'll try it, thanks!
 
Last edited:
Temp0 said:
That trapezoid idea might work, i'll try it, thanks!
This is the picture I was wondering if you drew.
 
No picture.
 
I meant I was wondering if he had drawn the trapezoid picture Halls had described. I didn't attach a picture.
 

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