Relating change in time to change in position and velocity

[OneObstacle]

I was looking back at some homework solutions I've solved earlier this term and I ran across this equation:

Δt = 2*Δx/(vf+vi)

Which seems to translate to:

Δt = Δx/v_ave

Is this an actual way of finding delta t? I got the answer right, but I can not understand or find where I got this equation.

EDIT: Can someone take this down? I found out I just rearranged d = (vf+vi)/2 * t

 

[PhanthomJay]

I was looking back at some homework solutions I've solved earlier this term and I ran across this equation:

Δt = 2*Δx/(vf+vi)

Which seems to translate to:

Δt = Δx/v_ave

Is this an actual way of finding delta t? I got the answer right, but I can not understand or find where I got this equation.

EDIT: Can someone take this down? I found out I just rearranged d = (vf+vi)/2 * t

Yes, correct, d = v_avet seems to be one of the most forgotten but helpful of the 5 motion equations for constant acceleration.