Relating change in time to change in position and velocity

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SUMMARY

The discussion centers on the equation Δt = 2*Δx/(vf+vi), which simplifies to Δt = Δx/vave, for calculating the change in time (Δt) based on change in position (Δx) and average velocity (vave). The user initially questioned the validity of this equation but later recognized it as a rearrangement of the formula d = (vf+vi)/2 * t, a fundamental equation in kinematics for constant acceleration. This highlights the importance of understanding the relationships between position, velocity, and time in physics.

PREREQUISITES
  • Understanding of kinematic equations
  • Familiarity with average velocity concepts
  • Basic algebra for rearranging equations
  • Knowledge of constant acceleration principles
NEXT STEPS
  • Study the five motion equations for constant acceleration
  • Learn how to derive average velocity from initial and final velocities
  • Explore practical applications of kinematic equations in physics problems
  • Practice solving problems involving Δx, Δt, vf, and vi
USEFUL FOR

Students studying physics, particularly those focusing on kinematics, educators teaching motion concepts, and anyone looking to reinforce their understanding of the relationships between time, position, and velocity.

OneObstacle
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I was looking back at some homework solutions I've solved earlier this term and I ran across this equation:

Δt = 2*Δx/(vf+vi)

Which seems to translate to:

Δt = Δx/vave

Is this an actual way of finding delta t? I got the answer right, but I can not understand or find where I got this equation.

EDIT: Can someone take this down? I found out I just rearranged d = (vf+vi)/2 * t
 
Last edited:
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OneObstacle said:
I was looking back at some homework solutions I've solved earlier this term and I ran across this equation:

Δt = 2*Δx/(vf+vi)

Which seems to translate to:

Δt = Δx/vave

Is this an actual way of finding delta t? I got the answer right, but I can not understand or find where I got this equation.

EDIT: Can someone take this down? I found out I just rearranged d = (vf+vi)/2 * t

Yes, correct, d = vavet seems to be one of the most forgotten but helpful of the 5 motion equations for constant acceleration.
 

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