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Relating change in time to change in position and velocity

  1. Oct 3, 2012 #1
    I was looking back at some homework solutions I've solved earlier this term and I ran across this equation:

    Δt = 2*Δx/(vf+vi)

    Which seems to translate to:

    Δt = Δx/vave

    Is this an actual way of finding delta t? I got the answer right, but I can not understand or find where I got this equation.

    EDIT: Can someone take this down? I found out I just rearranged d = (vf+vi)/2 * t
     
    Last edited: Oct 3, 2012
  2. jcsd
  3. Oct 3, 2012 #2

    PhanthomJay

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    Yes, correct, d = vavet seems to be one of the most forgotten but helpful of the 5 motion equations for constant acceleration.
     
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