Relating charge to potential difference

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Daishain
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Homework Statement


Ions with mass m and charge q are accelerated through a potential difference V. They then enter a uniform magnetic field perpendicular to their velocity and are deflected in a semicircular path of radius R

What potential difference V is needed so that singly ionized 12C atoms will have R= 50 cm in a 0.15T magnetic field?

radius R= 50 cm
magnetic field strength B= 0.15 T
mass m= 1.993 X10^-26 kg
charge q=?
linear velocity v=?
voltage difference V=?

Homework Equations


v=(R*|q|*B)/m
V=(0.5*m*v^2)/q

Not looking for a specific solution from here. I need a new way to equate the data. No matter how I slice it given the formulas and data provided, I cannot find the potential difference without either the particle's charge or its linear velocity.
 
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Daishain said:

Homework Statement


Ions with mass m and charge q are accelerated through a potential difference V. They then enter a uniform magnetic field perpendicular to their velocity and are deflected in a semicircular path of radius R

What potential difference V is needed so that singly ionized 12C atoms will have R= 50 cm in a 0.15T magnetic field?

radius R= 50 cm
magnetic field strength B= 0.15 T
mass m= 1.993 X10^-26 kg
charge q=?
linear velocity v=?
voltage difference V=?

Homework Equations


v=(R*|q|*B)/m
V=(0.5*m*v^2)/q

Not looking for a specific solution from here. I need a new way to equate the data. No matter how I slice it given the formulas and data provided, I cannot find the potential difference without either the particle's charge or its linear velocity.

What do you suppose the phrase "singly ionized" implies?
 
gneill said:
What do you suppose the phrase "singly ionized" implies?

*facepalm*

I had assumed it meant nothing more than that ions were produced and released in series. Thanks for pointing it out, I should be able to handle it from here.