Relating charge to potential difference

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SUMMARY

The discussion focuses on calculating the potential difference (V) required for singly ionized carbon-12 (12C) atoms to achieve a semicircular path radius (R) of 50 cm in a magnetic field (B) of 0.15 T. The relevant equations provided are v=(R*|q|*B)/m and V=(0.5*m*v^2)/q, where m is the mass of the ion (1.993 x 10^-26 kg). The challenge lies in determining the charge (q) and linear velocity (v) of the ions, which are necessary to compute the potential difference.

PREREQUISITES
  • Understanding of ion mass and charge, specifically for singly ionized atoms.
  • Familiarity with the concepts of electric potential and magnetic fields.
  • Knowledge of the equations of motion for charged particles in magnetic fields.
  • Basic proficiency in algebra and physics problem-solving techniques.
NEXT STEPS
  • Research the properties of singly ionized carbon-12 (12C) ions, including their charge.
  • Learn how to derive linear velocity (v) from the radius of curvature (R) in magnetic fields.
  • Explore the relationship between kinetic energy and potential difference in charged particles.
  • Investigate the effects of varying magnetic field strengths on the motion of charged particles.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone involved in particle physics or electromagnetic theory, particularly those studying the behavior of ions in magnetic fields.

Daishain
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Homework Statement


Ions with mass m and charge q are accelerated through a potential difference V. They then enter a uniform magnetic field perpendicular to their velocity and are deflected in a semicircular path of radius R

What potential difference V is needed so that singly ionized 12C atoms will have R= 50 cm in a 0.15T magnetic field?

radius R= 50 cm
magnetic field strength B= 0.15 T
mass m= 1.993 X10^-26 kg
charge q=?
linear velocity v=?
voltage difference V=?

Homework Equations


v=(R*|q|*B)/m
V=(0.5*m*v^2)/q

Not looking for a specific solution from here. I need a new way to equate the data. No matter how I slice it given the formulas and data provided, I cannot find the potential difference without either the particle's charge or its linear velocity.
 
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Daishain said:

Homework Statement


Ions with mass m and charge q are accelerated through a potential difference V. They then enter a uniform magnetic field perpendicular to their velocity and are deflected in a semicircular path of radius R

What potential difference V is needed so that singly ionized 12C atoms will have R= 50 cm in a 0.15T magnetic field?

radius R= 50 cm
magnetic field strength B= 0.15 T
mass m= 1.993 X10^-26 kg
charge q=?
linear velocity v=?
voltage difference V=?

Homework Equations


v=(R*|q|*B)/m
V=(0.5*m*v^2)/q

Not looking for a specific solution from here. I need a new way to equate the data. No matter how I slice it given the formulas and data provided, I cannot find the potential difference without either the particle's charge or its linear velocity.

What do you suppose the phrase "singly ionized" implies?
 
gneill said:
What do you suppose the phrase "singly ionized" implies?

*facepalm*

I had assumed it meant nothing more than that ions were produced and released in series. Thanks for pointing it out, I should be able to handle it from here.
 

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