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Relating charge to potential difference

  1. Apr 14, 2012 #1
    1. The problem statement, all variables and given/known data
    Ions with mass m and charge q are accelerated through a potential difference V. They then enter a uniform magnetic field perpendicular to their velocity and are deflected in a semicircular path of radius R

    What potential difference V is needed so that singly ionized 12C atoms will have R= 50 cm in a 0.15T magnetic field?

    radius R= 50 cm
    magnetic field strength B= 0.15 T
    mass m= 1.993 X10^-26 kg
    charge q=?
    linear velocity v=?
    voltage difference V=?

    2. Relevant equations
    v=(R*|q|*B)/m
    V=(0.5*m*v^2)/q

    Not looking for a specific solution from here. I need a new way to equate the data. No matter how I slice it given the formulas and data provided, I cannot find the potential difference without either the particle's charge or its linear velocity.
     
  2. jcsd
  3. Apr 14, 2012 #2

    gneill

    User Avatar

    Staff: Mentor

    What do you suppose the phrase "singly ionized" implies?
     
  4. Apr 14, 2012 #3
    *facepalm*

    I had assumed it meant nothing more than that ions were produced and released in series. Thanks for pointing it out, I should be able to handle it from here.
     
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