# Relating charge to potential difference

1. Apr 14, 2012

### Daishain

1. The problem statement, all variables and given/known data
Ions with mass m and charge q are accelerated through a potential difference V. They then enter a uniform magnetic field perpendicular to their velocity and are deflected in a semicircular path of radius R

What potential difference V is needed so that singly ionized 12C atoms will have R= 50 cm in a 0.15T magnetic field?

magnetic field strength B= 0.15 T
mass m= 1.993 X10^-26 kg
charge q=?
linear velocity v=?
voltage difference V=?

2. Relevant equations
v=(R*|q|*B)/m
V=(0.5*m*v^2)/q

Not looking for a specific solution from here. I need a new way to equate the data. No matter how I slice it given the formulas and data provided, I cannot find the potential difference without either the particle's charge or its linear velocity.

2. Apr 14, 2012

### Staff: Mentor

What do you suppose the phrase "singly ionized" implies?

3. Apr 14, 2012

### Daishain

*facepalm*

I had assumed it meant nothing more than that ions were produced and released in series. Thanks for pointing it out, I should be able to handle it from here.