Relation for Kinetic energy and the lorentz factor.

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SUMMARY

The discussion centers on deriving the kinetic energy (KE) as a function of the Lorentz factor (γ) in the context of special relativity. The total energy equation is given by Etot = γm0c2, and the relationship is established as KE = γm0c2 - m0c2. The challenge lies in eliminating the mass variable from the equation while maintaining the dependence solely on the Lorentz factor and constants. Participants emphasize that mass and energy properties are essential for distinguishing between particles like electrons and protons.

PREREQUISITES
  • Understanding of special relativity concepts, particularly the Lorentz factor (γ)
  • Familiarity with energy equations in physics, specifically Etot = γm0c2
  • Basic knowledge of algebraic manipulation to isolate variables
  • Concept of relativistic mass and its implications in kinetic energy calculations
NEXT STEPS
  • Research the derivation of kinetic energy in special relativity using the Lorentz factor
  • Study the implications of mass-energy equivalence in relativistic physics
  • Explore advanced topics in special relativity, such as relativistic momentum
  • Learn about the role of fundamental constants in physics equations, particularly in energy calculations
USEFUL FOR

Students of physics, educators teaching special relativity, and anyone interested in the mathematical relationships between kinetic energy and the Lorentz factor.

martinhiggs
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Homework Statement



I have to find a relation for kinetic energy as a function of the lorentz factor, KE(gamma). It can only depend on the lorentz factor or on a constant.

Homework Equations



E_{tot} = \gamma m_{0} c^{2}

E_{tot} = KE + m_{0}c^{2} = \sqrt{p^{2}c^{2} + m_{0}c^{4}}

\gamma = \sqrt{1 + \frac{v^{2}}{c^2}}

The Attempt at a Solution



I thought that the best place to start would be:

E_{tot} = KE +m_{0}c^{2}

KE = E_{tot} - m_{0}c^{2}

Also I know that

E_{tot} = \gamma m_{0}c^{2}

Substituting this in I get:

KE = \gamma m_{0}c^{2} - m_{0}c^{2}

I'm now not sure how to carry on, to get rid of the masses from the equation. Everything I try to do to remove them causes me to have another variable, like energy to then get rid of.

Any suggestions, pointers or help would be greatly appreciated, I've been stuck on this problem for 12 hours now!
 
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The Lorentz Factor I know is given by,

\gamma = \frac{1}{\sqrt{1-\beta^2}} where \beta = v/c

At any rate, aren't m0 and c just constants?
 
kreil's right. There has to be some property of the particle involved, like mass or energy, because otherwise what would distinguish, say, an electron from a proton? They could both have the same Lorentz factor but their kinetic energies would be vastly different.

If the problem really asks you to find an expression for the kinetic energy in terms of \gamma and fundamental constants only (like the speed of light), then you can go right back to your instructor and tell him/her that it's an impossible problem.
 
Sorry, I meant 1/... for the Lorentz factor, typed it out wrong.

Ah, ok, I wasn't thinking of mass as a constant, I see now. Thanks!
 

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